from operator import truediv , mul, add, sub 2 from math import sqrt 3 v def quad(a, b,c): Your code did not pass this test case. Input (stdin) #Determine the discriminant d=sub(mul (b, b), mul (mul(4,a),c)) #If d is zero then we have a single root if d==0: 1,4,4 6. 7 Your Output (stdout) 8 x=truediv(-b, (2*a)) 9. return x -2.0 10 #Compute and return roots else: Expected Output 11 12 x=truediv(add (-b,sqrt(d)),(2*a)) -2 13 return [x] 14 inl, in2, in3=input().split(",") 15 inl,in2, in3=int (inl),int(in2),int(in3) 16 x=quad (in1,in2,in3) Compiler Message Wrong Answer 17 vif x!=None: 18 print(x) 19 20 ###Call the function and print the result below. 21 | 22 # # #End

Computer Networking: A Top-Down Approach (7th Edition)
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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I did this code to find only one root of the quadratic formula. 

My Output = -2.0 

Expected Output should be = -2 ONLY (not mine which is -2.0, should only be -2)

What is wrong with my code? Thank you experts. 

from operator import truediv, mul, add, sub
2 from math import sqrt
3 v def quad (a, b,c):
1
Your code did not pass this test case.
Input (stdin)
4
#Determine the discriminant
d=sub(mul(b, b) , mul (mul(4, a),c))
#If d is zero then we have a single root
if d==0:
1,4,4
Your Output (stdout)
8
x=truediv(-b, (2*a))
9
return x
-2.0
10
#Compute and return roots
Expected Output
11
else:
x=truediv (add (-b, sqrt(d)),(2*a))
return [x]
12
13
14 inl,in2, in3=input().split(",")
15 inl,in2,in3=int(inl), int (in2), int(in3)
16 x=quad (inl1,in2, in3)
17 vif x!=None:
Compiler Message
Wrong Answer
18
print(x)
19
20
###Call the function and print the result below.
21
22
###End
Transcribed Image Text:from operator import truediv, mul, add, sub 2 from math import sqrt 3 v def quad (a, b,c): 1 Your code did not pass this test case. Input (stdin) 4 #Determine the discriminant d=sub(mul(b, b) , mul (mul(4, a),c)) #If d is zero then we have a single root if d==0: 1,4,4 Your Output (stdout) 8 x=truediv(-b, (2*a)) 9 return x -2.0 10 #Compute and return roots Expected Output 11 else: x=truediv (add (-b, sqrt(d)),(2*a)) return [x] 12 13 14 inl,in2, in3=input().split(",") 15 inl,in2,in3=int(inl), int (in2), int(in3) 16 x=quad (inl1,in2, in3) 17 vif x!=None: Compiler Message Wrong Answer 18 print(x) 19 20 ###Call the function and print the result below. 21 22 ###End
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