From experiments, you know the following thermochemical equations:5C(s) + 6H2(g) →C5H12(g) ΔH1 = - 146.3 kJH2O (l) → H2O(g) ΔH2 = + 44 kJH2(g) + ½ O2 (g) → H2O(g) ΔH3 = - 241.8 kJCO2(g) → C(s) + O2(g) ΔH4 = +393.5 kJUse the information above to find the value of ΔH in the reaction below. C5H12(g) + 8O2(g) → 5CO2(g) + 6H2O(l) ΔH

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