Given the following thermochemical equations: 1) 2N2(g) + 202(g) → 4NO(g) AH = 2(-180.5 kJ) 2) 4NH3(g) → 2N2(g) + 6H2(g) AH = -2(-91.8 kJ) 3) 6H2(g) + 302(g) → 6H20(g) AH = 6(-241.8 kJ) %3D Calculate the standard reaction enthalpy, AH°, for the reaction below. 4NH3(g) + 502(g) → 4NO(g) + 6H2O(g) AH° = [ ? ] kJ Enter either a + or - sign AND the magnitude. Use significant figures:

Given the following thermochemical equations: 2 OF2 (g) →→→ 02 (g) + 2 F2 (g) 2 CIF (g) + O2 (g) → C120 (g) + OF2 (g) CIF 3 (g) + O2 (g) → Cl20 (g) + 3/2 OF2 (g) AH = -49.4 kJ AH = +205.6 kJ AH = +266.7 kJ Calculate the enthalpy change (in kJ) for this reaction: CIF (g) + F2 (g) → CIF3 (g) Show your complete solution. Express your answer in two decimal places.

When methanol, CH, OH, is burned in the presence of oxygen gas, O₂, a large amount of heat energy is released. For this reason, it is often used as a fuel in high performance racing cars. The combustion of methanol has the balanced, thermochemical equation CH₂OH(g) + O₂(g) → CO₂(g) + 2 H₂O(1) AH = -764 kJ How much methanol, in grams, must be burned to produce 983 kJ of heat? mass: g

Given the following thermochemical equations, 2Cu (s) + S (s) · → Cu₂S (s) AH° = -79.5 kJ S (s) + O₂ (g) → SO₂ (g) AH° = −297 kJ Cu₂ S (s) +20₂ (g) → 2CuO (s) + SO₂ (g) AH° = -527.5 kJ calculate the standard enthalpy of formation (in kJ mole¹¹) of CuO (s).

When CO(g) reacts with NO(g) according to the following reaction, 373 kJ of energy are evolved for each mole of CO(g) that reacts. Complete the following thermochemical equation. 2CO(g) + 2NO(g)- →2CO₂(g) + N₂(g) ΔΗ = kJ

Given the following thermochemical equations P4(s) + 6C12(g) 4PCI3(g) AH = -2439 kJ/mol 4PCI5(g) → P4(s) + 10CI 2(g) AH = 3438 kJ/mol find the AH for the reaction below, PCI5(g) → PC|3(g) + Cl2(g) O A) +249.8 kJ/mol O B) +999 kJ/mol O C) -999 kJ/mol O D) -249.8 kJ/mol

Consider the hypothetical thermochemical equation 3 A + B → 2 C for which AH = 63.1 kJ/mol. Which one of the following reactions would have an enthalpy change of -2×AH? Here, AH refers to the enthalpy change of the original reaction. А) С — 3/2 А + 1/2 В B) 6 A + 2 B –→ 4 C С) 3/2 А + 1/2 В — С D) 4 C → 6 A + 2 B

What is the change in enthalpy for the reaction: 2B (s) + 3H2(g) → B2H6 (g) given these thermochemical equations? B2H6 (g) + 302 (g) →B2O3 (s) + 3 H₂O (g) AH = -2032 kJ 2B (s) + 3/2 O2 (g) → B2O3 (s) AH = -1272 kJ H2(g) + 1/2 O2 (g) → H2O (g) AH -241.8 kJ -4029 kJ +518.2 kJ +34.6 kJ -3546 kJ

If the following three thermochemical equations are added together, what is the resulting equation:2 XO2 (g) +2 CO (g) →→ 2 XO (g) + 2 CO2 (g)2 XO (g) + 2/3 CO2(g) →→ 2/3 X3O4 (s) + 2/3 CO (g)2/3 X3O4 (s) + 1/3 CO2 (g) →→ X2O3 (g) + 1/3 CO (g)     Question 17 options:   6 XO (g) + 2 CO2(g) →→ 2 X3O4 (s) + 2 CO (g)   2 XO2 (s) + CO (g) →→ X2O3 (s) + CO2 (g)   C (s) + 3 XO2 (g) →→ X3O4 (g) + CO2 (g)   2 X3O4 (s) + CO2 (g)  →→ 3 X2O3 (g) + CO (g)   CO (g) + XO2 (g) →→ XO (g) + CO2 (g)