From a normal distribution with μ = 76 and σ = 6.3, samples of size 48 are chosen to create a sampling distribution. In the sampling distribution determine the probability that a sample mean is at least 73.927. P(73.927 ≤ ¯x P(73.927 ≤ ¯x) = IMPORTENT----> [three decimal accuracy]

In analyzing hits by bombs in a past war, a city was subdivided into 638 regions, each with an area of 1-mi². A total of 529 bombs hit the combined area of 638 regions. The Poisson distribution applies because we are dealing with the occurrences of an event (bomb hits) over some interval (a region with area of 1-mi². Find the mean number of hits per region: mean = Find the standard deviation of hits per region: standard deviation If a region is randomly selected, find the probability that it was hit exactly twice. (Report answer accurate to 4 decimal places.) P(X = 2) = ans = = Based on the probability found above, how many of the 638 regions are expected to be hit exactly twice? (Round answer to a whole number.) If a region is randomly selected, find the probability that it was hit at most twice. (Report answer accurate to 4 decimal places.) P(X ≤ 2) = =

Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with mean 114.5 ft and standard deviation 58.7 ft. 200 trees. The bell curve below represents the You intend to measure a random sample of n distibution of these sample means. The scale on the horizontal axis is the standard error of the sampling distribution. Complete the indicated boxes, correct to two decimal places. > Next Question

Use the Central Limit Theorem to find the probability of the indicated event, assuming that the distribution of the population data is unknown. The amount of time students spend checking their phones during a lecture period has a mean of 9 minutes and standard deviation of 2 minutes. What is the probability that a sample of 30 students will spend an average of at most 9.7 minutes checking their phones during a lecture period? Standard Normal Distribution Table P( X̄  < 9.7)=__

The lengths of human pregnancies have mean 266 days and standarddeviation 16 days. Suppose that a sample of 100 pregnancies israndomly selected and the mean length (x-bar) is computed. a. Why can we assume that the distribution of the sample mean isapproximately normal? b. State the mean and compute the standard deviation of thedistribution of Express the standard deviationaccurate to 1 decimal place.

Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the probability of a bone density test score greater than 0.96. Sketch the region. Choose the correct graph below. О А. В. D. -0.96 0.96 0.96 0.96 -0.96

33. From a normal distribution with μ = 85 and σ = 4.6, samples of size 50 are chosen to create a sampling distribution. In the sampling distribution determine the probability that a sample mean is at most 86.184. P(x¯ ≤ 86.184) =     [three decimal accuracy]

Suppose x has a distribution with mean 22 and standard deviation 16. If a random sample of size n=36 is drawn find p(22<×<24)

Consider the normal distribution with mean 52 and standard deviation 8. Find the area under the normal curve and above the interval [46,00) on the horizontal axis. Click the icon to view the area under the standard normal curve table. The area under the given normal curve and above the interval [46,00) on the horizontal axis is approximately (Round to four decimal places as needed.) ECOCH

A dishwasher has a mean lifetime of 12 years with an estimated standard deviation of 1.25 years. The lifetime of a dishwasher is normally distributed. Suppose you are a manufacturer and you take a sample of 15 dishwashers that you made.  Find probability that the sample mean lifetime of the 15 randomly selected dishwashers is less than 12.6 (4 decimals) find the probability that the sample mean lifetime of the 15 randomly selected dishwashers is less than 11.4 years thank u for the help