he 4 conditions necessary to assume the sampling distribution of sample proportions follows a Normal distribution.

According to a survey in a country, 21% of adults do not own a credit card. Suppose a simple random sample of 200 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1 - p) 2 10 B. Approximately normal because ns0.05N and np(1- p) 2 10 O C. Not normal because ns0.05N and np(1 - p) < 10 O D. Approximately normal because ns0.05N and np(1- p) < 10 Determine the mean of the sampling distribution of p. Ha = 0.21 (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. GA = 0.029 (Round to three decimal places as needed.) (b) What is the probability that in a random…

If a normal sampling distribution can be used, identify the rejection region(s). Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice.

For any normal distribution, what is the probablity of selection a score less than the mean?

According to a survey in a country, 21% of adults do not own a credit card. Suppose a simple random sample of 200 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1 - p) 2 10 B. Approximately normal because ns0.05N and np(1 - p) 2 10 O C. Not normal because ns0.05N and np(1 - p) < 10 O D. Approximately normal because ns0.05N and np(1- p) < 10 Determine the mean of the sampling distribution of p. HA = 0.21 (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. On = 0.029 (Round to three decimal places as needed.) (b) What is the probability that in a random…

Define Random Sampling and the Distribution of the Sample Average?

What is the mean of the sampling distribution? (round to 3 decimal places)

When determining sample size what do you do if the sample proportion is unknown? What are the requirements for using a normal distribution as an approximation to a binomial distribution?

Suppose the true proportion of voters in the county who support a restaurant tax is 0.44. Consider the sampling distribution fpr the proportion of supporters with-sample size n = 111. What is the mean of this distribution? What is the standard error of this distribution? (Round your answer to two decimal places.) Submit Question

According to a survey in a country, 32% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because n <0.05N and np(1 – p)< 10 GB. Approximately normal because n<0.05N and np(1 - p) 2 10 CC. Not normal because ns0.05N and np(1 - p) 2 10 D. Approximately normal because n<0.05N and np(1 - p)< 10 Determine the mean of the sampling distribution of p. (Round to two decimal places as needed.) p Enter your answer in the answer box and then click Check Answer. ? 6. parts remaining Clear All Check Answer