Frictionless rollers support the side blocks vertically. The side blocks in turn support the 8lb block viafriction.A. At what friction coefficient is the motion of the 8 lb block impending?B. What is the friction force on the left side of the 8 lb block when μ = 0.8?C. Given your result from part B, at μ=0.8 is the 8 lb block:a. Static but not impendingb. At impending motionc. Moving against kinetic friction16 lb·μ=?16 lb8 lbupudu u än pääs *ɔ 'q = =

Answered: Frictionless rollers support the side…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Problem 6.2: The aluminum rod ABC (E=10.1x10° psi) (Figure 6.19), which consists of two cylindrical portions AB and BC, is to be replaced with a cylindrical steel rod DE (E=29x10° psi) of the same overall length. Determine the minimum required diameter d of the steel rod if its vertical deformation 28 kips 25 kips A D 12 in. -1.5 in. is not to exceed the deformation of the aluminum rod under the same load and if the allowable stress in the steel rod is not to exceed 24 ksi. B - 2.25 in. 18 in. E Figure 6.19
Answer in two decimal places please
NOTE: The standard pull of the tape is 5kg while the team pulled only at 4kg The field temperature is 300 while the standard temp of the tape is 200 The cross sectional area of the tape is 0.05cm2. The coefficient of linear expansion is 0.000011610C and the modulus of elasticity of steel is given to be 2.0 x 106 kg/cm. The tape used here is a 50m steel tape. Determine the actual length of each lines
Question 6 of 11 -/10 E View Policies Current Attempt in Progress The stresses shown in the figure act at a point on the free surface of a machine component. If o= 45 MPa in the direction shown, determine the normal stress oy at the point. 27 MPa 30° 50 MPa O -16.3 MPa O -19.5 MPa O-22.8 MPa O-17.2 MPa O -20.5 MPa Attempts: 0 of 1 used Submit Answer Save for Later
Show free body diagram, and complete process.
A stat of stress is specified in Figure. By using Mohr's circle determine the normal and shearing stresses on (a) the principal planes, (b) the planes of maximum shearing stress. 20 MPa 32 MPa 10 MPa 10 MPa 32 MPa 20 MPa I need a clear answer by hand, not by keyboard and fast answer within 20 minutes. Thank you | dybala
A flat steel bar, 30 mm wide by 2 mm thick and 1.6 m long, is bent by couples applied at the ends so that the midpoint deflection is 23 mm. Compute the maximum stress in the bar. Use E =210GPA. Answer must be in MPa.
Please answer correctly. Please I need this ASAP. thank you Note: The tolerance is ± 1 in the third significant digit
Problem 04.107 - Maximum load carrying capacity of a milled rod with known allowable stress A milling operation was used to remove a portion of a solid bar of square cross section. Knowing that a = 30 mm, d = 20 mm, and all = 54 MPa, determine the magnitude P of the largest force that can be safely applied at the centers of the ends of the bar. The magnitude P of the largest force that can be safely applied at the centers of the of the bar is KN.
A rectangle column 500 mm x200 mm in cross-section is subjected to a compression load 1000 KN, the stress on the column is: a. 30 MPa b. 10 MPa C. 50 MPa d. 20 MPa
A rectangular steel block is 4 inches long in the x direction, 3 inches longin the y direction, and 4 inches long in the z direction. The block issubjected to a triaxial loading of three uniformly distributed forces asfollows: 48 kips tension in the x direction, 60 kips compression in the ydirection, and 54 kips tension in the z direction. If ν = 0.30 and E = 29 ×106 psi, determine the single uniformly distributed load in the x directionthat would produce the same deformation in the y direction as the originalloading. Note provide a diagram/figure. -Draw and label the diagram correctly, No diagram in the solution will be marked wrong. -Shortcut solution will be marked wrong.- Direction of the assumption of the equilibrium equation must be shown, no direction will be marked wrong.
FE.Question 3

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