four_dice = np.zeros(Lpow(6,4),5]) n = 0 outcomes = [1,2,3,4,5,6] for i in outcomes: for j in outcomes: for k in outcomes: for l in outcomes: four_dice[n, :] = [i,j,k,1,i+j+k+l] n +=1 four_dice_df = pd.DataFrame(four_dice,columns-('Dice 1','Dice 2','Dice 3','Dice 4','Total'))

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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The code below creates a table for the outcomes when 4 dice are rolled, and stores them as a DataFrame.

Extend the code to print out the number of ways to obtain 15 as the total when 4 dice are rolled simultaneously.

 

 

four_dice =
2
np.zeros([pow(6,4),5])
n = 0
3
outcomes =
[1,2,3,4,5,6]
4 v for i in outcomes:
for j in outcomes:
for k in outcomes:
for 1 in outcomes:
7 v
8
9
four_dice[n,:]
[i,j,k,1,i+j+k+1]
n +=1
10 |four_dice_df
pd. DataFrame(four_dice,columns=('Dice 1','Dice 2','Dice 3','Dice 4','Total'))
> > > ►
Transcribed Image Text:four_dice = 2 np.zeros([pow(6,4),5]) n = 0 3 outcomes = [1,2,3,4,5,6] 4 v for i in outcomes: for j in outcomes: for k in outcomes: for 1 in outcomes: 7 v 8 9 four_dice[n,:] [i,j,k,1,i+j+k+1] n +=1 10 |four_dice_df pd. DataFrame(four_dice,columns=('Dice 1','Dice 2','Dice 3','Dice 4','Total')) > > > ►
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