Formula BF₁ HCN H₂Te Dot Requirement (1) = 40 N=8+5(8) A = 3+ 4(7) + 1= 32 S= 8 (1) N = A = S= (1) N= A= S= Dot Formula (2) (2) (2) :F: F:B:F: :F: Electronic Geometry (3a) (3a) (3b) (4a) TT (3a) (3b) (4a) TT show bond angles Molecular Geometry F Bonds (7a) (3b) tetrahedral (4a) Types of bonds #bonds (4b) hybridization -- sp³-B B-F J 4. none sp³ F F (7b) Tetrahedral Bonds (7a) (7b) (7a) (7b) 109.50 # # (Circle one) Ifpolar, show dipole (8a) Symmetrical YN (8b) Polar Y N (8a) Symmetrical Y N (8b) Polar Y N (4b) hybridization Ht none. N (8a) Symmetrical Y N (8b) Polar Y N (4b) hybridization H те

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Chapter1: Chemical Foundations
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Formula
BF₁
HCN
H₂Te
Dot Requirement
(1)
N = 8+5(8) = 40
A = 3+ 4(7) + 1 = 32
S=
8
(1)
N =
A =
S=
(1)
N=
A=
S=
Dot Formula
(2)
(2)
(2)
A
B:F:
:F:
Electronic
Geometry
(3a)
TT
(3a)
(3b)
(4a)
TT
(3a)
(3b)
ab k
show bond angles
Molecular
Geometry
(4a)
(7a)
(3b) tetrahedral
(48) Types of bonds #bonds (4b) hybridization -element
B-F
4.
none
F
Bonds
(7b) Tetrahedral
(7a)
(7b)
F
(7a)
(7b)
#
(Circle one)
Ifpolar, show dipole
109.50 (8a) Symmetrical
N
F
#1
Y
(8b) Polar
Y
sp³
sp³
(8a) Symmetrical
N
Y
(8b) Polar
Y
ZPIE K
(4b) hybridization
it none
(8a) Symmetrical
Y N
(8b) Polar
N
Y N
(4b) hybridization
H
Te
Molecular Models
Lab
Section
Lab Instructor
Date
Transcribed Image Text:Formula BF₁ HCN H₂Te Dot Requirement (1) N = 8+5(8) = 40 A = 3+ 4(7) + 1 = 32 S= 8 (1) N = A = S= (1) N= A= S= Dot Formula (2) (2) (2) A B:F: :F: Electronic Geometry (3a) TT (3a) (3b) (4a) TT (3a) (3b) ab k show bond angles Molecular Geometry (4a) (7a) (3b) tetrahedral (48) Types of bonds #bonds (4b) hybridization -element B-F 4. none F Bonds (7b) Tetrahedral (7a) (7b) F (7a) (7b) # (Circle one) Ifpolar, show dipole 109.50 (8a) Symmetrical N F #1 Y (8b) Polar Y sp³ sp³ (8a) Symmetrical N Y (8b) Polar Y ZPIE K (4b) hybridization it none (8a) Symmetrical Y N (8b) Polar N Y N (4b) hybridization H Te Molecular Models Lab Section Lab Instructor Date
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