Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
Bartleby Related Questions Icon

Related questions

bartleby

Concept explainers

Question
100%

Need help with part b. Thank you!

Here is the transcription and explanation of the educational content provided in the image:

---

**1. Carboxy Rhodamine emits a photon of light with a wavelength of \(5.95 \times 10^{-7}\) m.**

   a) **What is the frequency (s\(^{-1}\)) of the emitted photon?**

   - **Solution:**
     \[
     \text{Wavelength} = 5.95 \times 10^{-7} \, \text{m}
     \]
     We need to find the frequency (ν) of the emitted photon using the formula:
     \[
     \nu = \frac{c}{\lambda}
     \]
     where \( c = 3.00 \times 10^8 \, \text{m/s} \) is the speed of light.
     Plugging in the values:
     \[
     \nu = \frac{3.00 \times 10^8 \, \text{m/s}}{5.95 \times 10^{-7} \, \text{m}}
     \]
     \[
     \nu = 5.04 \times 10^{14} \, \text{s}^{-1}
     \]

   b) **What is the energy (in cal) of the emitted photon?**

   - The calculation for the energy in calories is not provided in the image.

---

**Explanation of Diagram/Graph:**

The problem includes handwritten calculations to determine the frequency of light. The formula shown depicts how frequency (\(\nu\)) is calculated using the known speed of light \(c\) and the given wavelength \(\lambda\). No additional diagrams or graphs are present.
expand button
Transcribed Image Text:Here is the transcription and explanation of the educational content provided in the image: --- **1. Carboxy Rhodamine emits a photon of light with a wavelength of \(5.95 \times 10^{-7}\) m.** a) **What is the frequency (s\(^{-1}\)) of the emitted photon?** - **Solution:** \[ \text{Wavelength} = 5.95 \times 10^{-7} \, \text{m} \] We need to find the frequency (ν) of the emitted photon using the formula: \[ \nu = \frac{c}{\lambda} \] where \( c = 3.00 \times 10^8 \, \text{m/s} \) is the speed of light. Plugging in the values: \[ \nu = \frac{3.00 \times 10^8 \, \text{m/s}}{5.95 \times 10^{-7} \, \text{m}} \] \[ \nu = 5.04 \times 10^{14} \, \text{s}^{-1} \] b) **What is the energy (in cal) of the emitted photon?** - The calculation for the energy in calories is not provided in the image. --- **Explanation of Diagram/Graph:** The problem includes handwritten calculations to determine the frequency of light. The formula shown depicts how frequency (\(\nu\)) is calculated using the known speed of light \(c\) and the given wavelength \(\lambda\). No additional diagrams or graphs are present.
Expert Solution
Check Mark
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY