Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Need help with part b. Thank you!
![Here is the transcription and explanation of the educational content provided in the image:
---
**1. Carboxy Rhodamine emits a photon of light with a wavelength of \(5.95 \times 10^{-7}\) m.**
a) **What is the frequency (s\(^{-1}\)) of the emitted photon?**
- **Solution:**
\[
\text{Wavelength} = 5.95 \times 10^{-7} \, \text{m}
\]
We need to find the frequency (ν) of the emitted photon using the formula:
\[
\nu = \frac{c}{\lambda}
\]
where \( c = 3.00 \times 10^8 \, \text{m/s} \) is the speed of light.
Plugging in the values:
\[
\nu = \frac{3.00 \times 10^8 \, \text{m/s}}{5.95 \times 10^{-7} \, \text{m}}
\]
\[
\nu = 5.04 \times 10^{14} \, \text{s}^{-1}
\]
b) **What is the energy (in cal) of the emitted photon?**
- The calculation for the energy in calories is not provided in the image.
---
**Explanation of Diagram/Graph:**
The problem includes handwritten calculations to determine the frequency of light. The formula shown depicts how frequency (\(\nu\)) is calculated using the known speed of light \(c\) and the given wavelength \(\lambda\). No additional diagrams or graphs are present.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2f9c3ee4-3184-4dac-b08f-3b624081feab%2F480b674f-d9db-424e-9bd4-02d4c9ed665d%2F339btne_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Here is the transcription and explanation of the educational content provided in the image:
---
**1. Carboxy Rhodamine emits a photon of light with a wavelength of \(5.95 \times 10^{-7}\) m.**
a) **What is the frequency (s\(^{-1}\)) of the emitted photon?**
- **Solution:**
\[
\text{Wavelength} = 5.95 \times 10^{-7} \, \text{m}
\]
We need to find the frequency (ν) of the emitted photon using the formula:
\[
\nu = \frac{c}{\lambda}
\]
where \( c = 3.00 \times 10^8 \, \text{m/s} \) is the speed of light.
Plugging in the values:
\[
\nu = \frac{3.00 \times 10^8 \, \text{m/s}}{5.95 \times 10^{-7} \, \text{m}}
\]
\[
\nu = 5.04 \times 10^{14} \, \text{s}^{-1}
\]
b) **What is the energy (in cal) of the emitted photon?**
- The calculation for the energy in calories is not provided in the image.
---
**Explanation of Diagram/Graph:**
The problem includes handwritten calculations to determine the frequency of light. The formula shown depicts how frequency (\(\nu\)) is calculated using the known speed of light \(c\) and the given wavelength \(\lambda\). No additional diagrams or graphs are present.
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