Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- In (Figure 1), Tzy = 57.7 MPa. Figure 80 MPa T ▼ Part A Determine the principal stresses. Specify the orientation of the element. Express your answers, separated by commas, to three significant figures. Choose the angle from the half-interval (-90°; 90°]. 01, 02, 0p1 = Submit Part B IVE] ΑΣΦ 41 Ivec Request Answer Submit T max =, Javg, ₂ = In-plane Determine the maximum in-plane shear stress and average normal stress. Specify the orientation of the element. Express your answers, separated by commas, to three significant figures. Choose the angle from the half-interval (-90°; 90°]. Request Answer < Return to Assignment 15] ΑΣΦ 41 | vec ↑ S ? Provide Feedback D MPa, MPa, º ? MPa, MPa, 0arrow_forwardP= 200 lbs |=2" T 250 in-Ibs Qt. DRAW STRESS STATES いITH A SQLARE ECEMENT エN xY AXES Label with stress values Q2 DRAW MOHR'S CIRCLE AT A Q3.CALCULATE PRINCIPAL STRESSES AND DRAW THE PLANE FoR ri$ a IN THE SCHEHATIC Draw element rotated to principal planes and label with stress values and rotation anglearrow_forward1. A part made of Aluminum 6061-T6 has a yield strength = 400 MPa. For each stress state below, draw all 3 Mohr's circles, find the principal stresses, and calculate the safety factor against yield using both the distortion-energy (von Mises) and maximum shear stress (Tresca) criterions. (If relevant) A clearly labeled diagram (or diagrams) clearly pertaining to your analysis with a coordinate system and relevant labels. Final answer with appropriate units and significant figures. You can use the fprintf() command in MATLAB to format numerical results A 2-3 sentence reflection on your answer. Does it make sense? Why or why not? What are some implications?arrow_forward
- Use mohr' circlearrow_forwardThe stress-strain curve for mild steel is shown in figure given below. Choose the correct option referring to both figure and table. R Point on the graph Description of the point 1. Upper yield point 2. Ultimate tensile strength P. Q. 3. Proportionality limit 4. Elastic limit 5. Lower yield point U. 6. Failure ORSTarrow_forward3. Assume the plane stress state: ơ1 = 0, 02 = 20, T12 = 15 (all stresses in ksi). If oz alone is increased until the maximum shear stress t1, in the material reaches ±20 ksi, what is the value of o, at this point? HINT: this is relatively easy to figure out if you construct a Mohr's circle for the initial stress state and then consider what happens if o, is replaced with Ao2 and you solve for A when the maximum shear stress (from the circle geometry) reaches ±20 ksi.arrow_forward
- Fined the stress in each segment and the displacement in each segmentarrow_forwardPlease don't provide handwritten solution .....arrow_forwardThe cantilevered rectangular bar is subjected to the force of 5 kip. Suppose that L = 17 in. (Figure 1) Figure 1.5 in. A 1.5 in. 1 in. 1 in. B L 1 of 1 > 1.5 in. 1.5 in.j T 3 in. H 3 in. 5 kip Part A Determine the principal stresses at point A Express your answers in kilopounds per square inch to three significant figures. Enter your answers separated by a comma. 01,02 = Submit Provide Feedback ΓΙ ΑΣΦ | | Request Answer vec 5 ? Review ksi Next >arrow_forward
- Please solve all partarrow_forward← 2 Q go : Question 1 1. An element in plane stress on the fuselage of an airplane is subjected to compressive stresses in the horizontal direction and tensile stresses in the vertical direction (see figure 1). The shear stresses act in the directions shown in the same figure. (a) Use the stress transformation equation to determine the stresses acting on an element oriented at a clockwise angle of 40° from the horizontal. (b) Show that your answers are correct using Mohr's circle. [10] [10] 15MPa 25MPa 50MPa Figure 1: Plane stress element Question 2 The surface of an airplane wing is subjected to plane stress with normal stresses σx and σy and shear stress Txy, as shown in the figure. At a counterclockwise angle theta is 37° from the x axis, the normal stress is 49 MPa in tension, and at an angle theta equal 46°, it is 37 MPa in compression. If the stress Ox equals 135 MPa in tension, what are the stresses σy and Txy? [10] Txy Ox-135MP 3 Figure 2: Plane stress element e T DONA 00…arrow_forwardAnswer 3-19Please include solution and brief reflection.arrow_forward
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