For the wildtype E. coli two sugars influence the level of transcription of the lactose operon. Fill in the table with the choices (shown in parenthesis) in each column to show how these two sugars influence gene regulation. negative regulation Sugars in the growth media: CAMP levels positive regulation Relative level of Lac (high or low) operon transcription (highest, inbetween, lowest) оссurs оссurs (ves or no) | (yes or no) glucose present; lactose absent glucose present; lactose present glucose absent; lactose present

The fictional bacteria Plumbumbacter aurus converts the lead ions to gold ions and uses the resulting electrons to create ATP. aurus has the midas operon which includes the promoter (midasP), the operator (midasO), and eight genes that encode proteins involved in converting lead to gold. The midas operon is regulated by the protein encoded by the midasR gene and the presence of gold ions. When the concentration of gold ions is low, the midas operon is transcribed and the bacteria convert lead into gold. When the concentration of gold is high, the midas operon is off. To better understand regulation of the midas operon, you created P. aurus mutants. The midasR- mutant has a nonfunctional midasR, the midasO- mutant has a nonfunctional midasO, and the midasP-mutant has a nonfunctional midasP. Based on the data below, the midas operon has what type of transcription control? (negative inducible, negative repressible, positive inducible, positive repressible)  Strain Produces Gold in…

For the following genotypes of E. coli strains, state whetherenzyme activity is inducible (I), constitutive (C), or uninducible (U).Key to symbols in table:z = structural gene for  -galactosidasey = structural gene for permeasea = structural gene for transacetylasep = promoter (for lac operon)i = structural gene for the lac repressor (regulator gene)o = operator (binding site for repressor)Genotype                                 -gal (z)                       Permease (y)                         Transacetylase (a)i+ p+ oC z- y- a+i- p+ o+ z+ y- a- /i+ p- oc z- y+ a-i- p+ o+ z+ y- a+ /i+ p+ oc z- y+ a-i+ p+ o+ z- y- a+i- p- o+ z+ y- a+ /i- p+ o+ z- y+ a-iS p+ o+ z- y- a+i- p+ o+ z+ y- a+ /i+ p- oc z- y+ a-is p+ o+ z- y+ a+ /i+ p+ oc z+ y- a-i- p- o+ z+ y- a+ /i- p+ o+ z- y- a-is p+ oc z+ y- a+i+ p+ oc z+ y- a+

The organization and function of the lac operon in E. coli is shown in the following figures: XXI Transcription Repressor mRNA Translation RNA polymerase M M Flask ZYA XXXX Active M-repressor protein Repressor active, operon off. The repressor protein binds with the operator, preventing transcription from the operon. (a) An inducible operon Copyright © 2007 Pearson Education, Inc., publishing as Benjamin Cummings Allolactose (inducer) Carbon/Energy Source 0 Z MInactive repressor protein (a) An inducible operon Transcription Translation XXX Permease B-Galactosidase Transacetylase Operon mRNA 3 Repressor inactive, operon on. When the inducer allolactose binds to the repressor protein, the inactivated repressor can no longer block transcription. The structural genes are transcribed, ultimately resulting in the production of the enzymes needed for lactose catabolism. Copyright © 2007 Pearson Education, Inc., publishing as Benjamin Cummings Suppose you inoculate three flasks of minimal…