For the series-parallel network below caluate the following. Express your answer in polar notation+ V₁Z₁ =1||1₁+E = 12 V 20°) ZT2||=1₂ =13=VL =IoooX₁ = 60 I₁6Ω ΙVVN22Vxciff8 Ω12₂HiznHEXc, 12 Ωo units⁰ unitsº unitsOunitsº unitsº units

Given Data:An LC circuit with,AC supply voltage Impedance offered by the inductor Impedance offered…

For the series-parallel network below caluate the following. Express your answer in polar notation + V₂ Xc, 18 Ω 1₂ 13 th₁202 12 Ω E = 12 V 20º Z₁ = |= 4₁ = 1₂= 13 = VL = I moo X = 6 Ω I ZT 7 V 2 V 2 Xc₂ ° units ° units units units units ° units

For the series-parallel network below caluate the following. Express your answer in polar notation + V₂ Xc, 18 Ω 1₂ 13 th₁202 12 Ω E = 12 V 20º Z₁ = |= 4₁ = 1₂= 13 = VL = I moo X = 6 Ω I ZT 7 V 2 V 2 Xc₂ ° units ° units units units units ° units

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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Question

For the series-parallel network below caluate the following. Express your answer in polar notation
+ V₁
Z₁ =
1
||
1₁
+
E = 12 V 20°) ZT
2
||
=
1₂ =
13=
VL =
I
ooo
X₁ = 60 I₁
6Ω Ι
V
V
N
2
2
V
xciff
8 Ω
12₂
Hizn
HE
Xc, 12 Ω
o units
⁰ units
º units
O
units
º units
º units

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Step 1: Summarize the details given:

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Step 2: Find the total impedance and the total current.

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Step 3: Find the inductor current and the capacitor currents.

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Step 4: Find the inductor voltage.

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