3. Find the total admittance for the following parallel impedances: Z₁ = 0.5290° Z2 = 0.1Ω < – 90° / = Z3=5220° 5Ω
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- Convert the following instantaneous currents to phasors, using cos(t) as the reference. Give your answers in both rectangular and polar form. (a) i(t)=5002cos(t30) (b) i(t)=4sin(t+30) (c) i(t)=5cos(t15)+42sin(t+30)(a) Transform v(t)=75cos(377t15) to phasor form. Comment on whether =377 appears in your answer. (b) Transform V=5010 to instantaneous form. Assume that =377. (c) Add the two sinusoidal functions a(t) and b(t) of the same frequency given as follows: a(t)=A2cos(t+) and b(t)=B2cos(t+). Use phasor methods and obtain the resultant c(t). Does the resultant have the same frequency?Two impedances of Z = 100 +j50 Q and Z2 = 20 -j20 Q are connected in series. what is the magnitude of the equivalent impedance in 2? %3D %3D Your Answer: Answer
- Write a report to compare between Ac Through capacitance and AC through in inductance then: For the circuit shown beside, find the total impedance between a (and b and Circuit current (I j6N a 100 0 v 82 -j72 bTwo impedances Z1 = 2+j6 N and Z2 = 6-j12 Q are connected in series. What is the resultant impedance in the polar form? 10cis-36.9° O 10cis36.9° 10cis53.1° 10cis-53.1°root locus z plane
- R An RC parallel circuit. A 110-V, 60.0-Hz, AC line is connected in parallel to a resistor of 1000 Q and a capacitor of 1.00 μF, as shown in figure above. Find The capacitive reactance is must nearly. 2650 j2 0-2650 j 0-60 j 60jQThe type of the load whose current and voltage phasors are as shown in the phaser diagram is Im 90° - Re Pure capacitive load non-pure Inductive load Purse resistive load O Pure inductive load non-pure capacitive loadAn electrical engineer is working with a parallel AC circuit. The circuit draws 8 ohms on a resistive branch, and the angle of the total impedance is 35°. What is the approximate number of ohms on the inductive branch? O 0.7 O 4.59 O 5.6 O 6.55
- Sinusoidal and Complex Forcing Functions Convert from rectangular to polar coordinates: 100 – j 205 1000 + j 126The phasor of the impedance of an AC circuit has no vertical component. What does this mean? there are no reactive components in the AC circuit the resistance of the circuit is equal to the reactance of the reactive components the inductive reactance and capacitive reactance are equal in magnitude there are no inductors in the circuita) Find the total admittance YT in polar form and Draw the admittance diagram ,then Calculate the value of C in microfarads and L in Henries.