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- First normal form says: a. No nonkey columns depend on another nonkey column b. Every column that's not part of the primary key is fully dependent on the primary key. c. Eliminate repeated fields. d. None of the abovePATHS is a table that contains information about paths on a number line. The structure of PATHS is as follows, where x1 and x2 represent that there is a path from Coordinate x1 to Coordinate x2 (You can't move from Coordinate x2 to Coordinate x1 ). NAME ΤΥΡE NULLABLE X1 INT FALSE X2 INT FALSE Problem Please write an SQL statement that returns the beginning and end point of each path in PATHS . Sort them by the value of the beginning point in ascending order. Constraints • In the case where a direct path from Coordinate a to Coordinate b is available, no path from Coordinate b to Coordinate a will be given. |x1-x2| = 1 • No path will overlap with one another. Example Suppose that PATHS is as follows: x1 x2 1 2 2 3 4 7 7 6 This table can be visualized as follows: START END END START 7 8. 9 Therefore, your SQL statement must return the following: start end 1 4 8 6calculate_new_balance Given a starting balance (a number), and a list of transaction tuples, calculate the final balance for an account. Transaction tuples are of the shape ("description", amount, "withdrawal") , or ("description", amount, "deposit"). The last entry in the tuple will be either "withdrawal" or "deposit". Every withdrawal decreases the balance of the account by the specified amount, and every deposit increases the balance. The return value is the new account balance, as a number. (which could be negative) Sample calls should look like: >>> calculate_new_balance(100, [("payday", 20, "deposit"), ("new shoes", 50, "withdrawal"), ("illicit winnings", 200, "deposit")])270>>> calculate_new_balance(100, [])100
- Second normal form says: a. No nonkey columns depend on another nonkey column. b. Every column that's not part of the primary key is fully dependent on the primary key. c. Eliminate repeated fields. d. None of the aboveComputer Science please please any help ASAP Query #5: Code a query that will make use of SQL Server intrinsic functions and reference the Instructors table. Must have alias names for each column. First column: Display the instructors name as first name initial followed by a period and space and then last name such as B. Brown Second column: Display the year only for the hire date. Third column: Difference in months between today’s date and the hire date. Last column: Display the string literal ‘Full-time instructor’ if an instructor has a Status of F or return the string literal of ‘Adjunct instructor’ if they have a status of P. You can use the Case function or the IIF function.Database: CUSTOMER (CustomerID, LastName, FIrstName, Phone, EmailAddress) PURCHASE (InvoiceNumber, InvoiceDate, PreTaxAmount, CustomerID) PURCHASE_ITEM (InvoiceNumber, InvoiceLineNumber, Item Number, RetailPrice) ITEM (ItemNumber, ItemDesciption, Cost, ArtistLastName, ArtistFirstName) Write an SQL statement to show which cutomers bought which items, and include any items that have not been sold. Include CUSTOMER.LastName, CUSTOMER.FirstName, IvoiceNumber, InvoiceDate, ItemNumber, ItemDescription, ArtistLastName, and ArtistFirstName,. Use a join using JOIN ON syntax, and sort the results by ArtistLastName and ArtistFirstName in ascending order. Note that in Microsoft Access this require multiple queries. From Database Concepts 9th Ed. (Kroenke)
- A cake shop named "Whisk" has an online presence. It has multiple flavors of cakes supplied by various vendors. The manager wants to know the cost of the available quantity. Write a sql query to get the total cost of the available cakes. Code should run on Mysql. Data type along with the sample input and output is mentioned below:- Cake: Column Type Cake_Id int Flavor varchar(100) Cost int Producer varchar(20) Stock int Sample Input :- Cake: Cake_id Flavor Cost Producer Stock 1001 Vanilla 450 Just bake 8 1003 Chocolate 500 Flower Aura 12 1004 Red velvet 600 Bakingo 1 1005 Strawberry 700 Bigbasket 2 1006 Cinnamon 900 Creamy 1 1007 Vanilla 900 Creamy 2 1008 Mango 900 Just bake 2 1009 Strawberry 550 Creamy 2 Sample output - 17200Description The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +--- | Id | Name | Salary | ManagerId | +---- | 1 | 2 | 3 | 4 +---- | Joe | 70000 | 3 | Henry | 80000 | 4 | Sam | Max Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager. + | Employee | + | Joe + | 60000 | NULL | 90000 | NULL ISQL A table Products have: a name (TEXT) a description (TEXT) a unit cost stored in cents (INTEGER) and of course we also add an id column to identify them. Separately, we'd like to track the number of items in stock for each product. To do so we'll have a store and an inventory table. Stores have just an id and a name. Then, our inventory table should combine stores and products, listing how much of each product each store has in stock. a product_id (INTEGER) a store_id (INTEGER) a quantity (INTEGER) in stock Now we can insert some stores, products and inventory into our database. There are 2 stores -- one called NY and one called NJ. There are 2 products we are concerned with. Their names are sneakers, costing $220 (remember this is dollars!) and boots costing $350. Use any description for each that you'd like. NY has 4 sneakers in stock and 3 boots. NJ has 5 sneakers in stock and no boots. Insert the above data into the tables you have created.