DescriptionThe Employee table holds all employees including their managers. Every employeehas an Id, and there is also a column for the manager Id.+---| Id | Name | Salary | ManagerId |+----| 1| 2| 3| 4+----| Joe | 70000 | 3| Henry | 80000 | 4| Sam| MaxGiven the Employee table, write a SQL query that finds out employees who earnmore than their managers. For the above table, Joe is the only employee whoearns more than his manager.+| Employee |+| Joe+| 60000 | NULL| 90000 | NULLI

Description The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +-- | Id | Name | Salary | ManagerId | | ----+ | 1 | Joe | 70000 | 80000 | 2 | Henry | 3 | Sam | 4 | Max +- Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager. + | Employee | +- | Joe +- | 3 | 4 | 60000 | NULL | 90000 | NULL I

Description The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +-- | Id | Name | Salary | ManagerId | | ----+ | 1 | Joe | 70000 | 80000 | 2 | Henry | 3 | Sam | 4 | Max +- Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager. + | Employee | +- | Joe +- | 3 | 4 | 60000 | NULL | 90000 | NULL I

Np Ms Office 365/Excel 2016 I Ntermed

1st Edition

ISBN:9781337508841

Author:Carey

Publisher:Carey

Chapter9: Working With Text Functions And Creating Custom Formats

Section: Chapter Questions

Problem 3RA

See similar textbooks

Similar questions

In Sql Oracle Apex application, Using GROUPING SETS, write a query to show the following groupings:• department_id, manager_id, job_id• manager_id, job_id• department_id, manager_id
PL/SQL Question I need to build pl/sql block that prompts a user for the number of visitors each day for the past 5 days and then displays the average number of visitors per day. For example; day 1: 19 day 2: 21 day 3: 23 ... The avg number of visitors is: ___ like this.
A cake shop named "Whisk" has an online presence. It has multiple flavors of cakes supplied by various vendors. The manager wants to know the cost of the available quantity. Write a sql query to get the total cost of the available cakes. Code should run on Mysql. Data type along with the sample input and output is mentioned below:- Cake: Column Type Cake_Id int Flavor varchar(100) Cost int Producer varchar(20) Stock int Sample Input :- Cake: Cake_id Flavor Cost Producer Stock 1001 Vanilla 450 Just bake 8 1003 Chocolate 500 Flower Aura 12 1004 Red velvet 600 Bakingo 1 1005 Strawberry 700 Bigbasket 2 1006 Cinnamon 900 Creamy 1 1007 Vanilla 900 Creamy 2 1008 Mango 900 Just bake 2 1009 Strawberry 550 Creamy 2 Sample output - 17200
SQL: Create a SQL query that uses an uncorrelated subquery and no joins to display the descriptions for products provided by a vendor in area code 615. Remember, the main difference between a correlated subquery and uncorrelated subquery is that, in a correlated subquery, the inner query is dependent upon the outer query, while, with an uncorrelated query, the inner query does not depend upon the outer query. Instead, it runs just once. You should NOT use union, minus, or intersect in this query. The outer query will use the PRODUCT table and the inner query will use the VENDOR table [hint: you should have 9 records of output]. My code: select p_descript from product where (select v_areacode from vendor where v_areacode = '615' ; I am getting this error, problem is I can't see what is missing any assistance is appreciated. ORA-00936: missing expression
SQL A table Products have: a name (TEXT) a description (TEXT) a unit cost stored in cents (INTEGER) and of course we also add an id column to identify them. Separately, we'd like to track the number of items in stock for each product. To do so we'll have a store and an inventory table. Stores have just an id and a name. Then, our inventory table should combine stores and products, listing how much of each product each store has in stock. a product_id (INTEGER) a store_id (INTEGER) a quantity (INTEGER) in stock Now we can insert some stores, products and inventory into our database. There are 2 stores -- one called NY and one called NJ. There are 2 products we are concerned with. Their names are sneakers, costing $220 (remember this is dollars!) and boots costing $350. Use any description for each that you'd like. NY has 4 sneakers in stock and 3 boots. NJ has 5 sneakers in stock and no boots. Insert the above data into the tables you have created.
*Develop a SQL Query Display all the resorts names whose star-rating ranges between 4 and 5. Sort the result set in the ascending order of star rating. RESORT MANAGEMENT SYSTEM Town Pointofinterest Manager townID Number PK managerID Number PK pointID Number PK townname Varchar(30) describe Varchar(30) name varchar(30) state varchar(30) opentime varchar(10) address varchar(30) %23 longitude varchar(30) varchar(20) varchar(15) closetime varchar(10) city varchar(30) Number latitude FK townID Number summertemp HAS phone wintertemp Number sealevel Number GIVES Resort Guest Review РK resortiD Number guestID Number PK FK,PK guestiD Number resortName varchar(30) name varchar(30) FK,PK resortID Number street varchar(30) MANADES address varchar(30) + varchar(20) dateofreview Date townname varchar(30) BOOKS country email varchar(30) FK townid Number varchar(150) comments phone varchar(15) starRating Number FK managerID Number Booking HAS PK bookingID FK guestid Number CabinCost HAS Number HAS…
WorksOn Database: Employee (EmployeeNumber, EmployeeName, BirthDate, Title, Salary, DepartmentNumber) Project (ProjectNumber, ProjectName, Budget, DepartmentNumber) Department (DepartmentNumber, DepartmentName, ManagerNumber) WorksOn (EmployeeNumber, ProjectNumber, Responsibility, Hours) Questions: 1) Write an SQL query that returns the project number and name for projects with a budget no greater than $1,050,000. 2) Write an SQL query that returns all works on records where hours worked is less than 5 and the responsibility is 'Manager'. 3) Write an SQL query that returns the employees (number and name only) who have a title of 'EE' or 'SA' and make more than $50,000. 4) Write an SQL query that returns the employees (name and salary only) in department 'D1' ordered by decreasing salary. 5) Write an SQL query that returns the departments (all fields) ordered by descending department name.
PATHS is a table that contains information about paths on a number line. The structure of PATHS is as follows, where x1 and x2 represent that there is a path from Coordinate x1 to Coordinate x2 (You can't move from Coordinate x2 to Coordinate x1 ). NAME ΤΥΡE NULLABLE X1 INT FALSE X2 INT FALSE Problem Please write an SQL statement that returns the beginning and end point of each path in PATHS . Sort them by the value of the beginning point in ascending order. Constraints • In the case where a direct path from Coordinate a to Coordinate b is available, no path from Coordinate b to Coordinate a will be given. |x1-x2| = 1 • No path will overlap with one another. Example Suppose that PATHS is as follows: x1 x2 1 2 2 3 4 7 7 6 This table can be visualized as follows: START END END START 7 8. 9 Therefore, your SQL statement must return the following: start end 1 4 8 6
If I have a table in sql database phpmyadmin the table's column : ID Name Salary City 1 John 200 London 2 Eric 300 Paris 3 Michael 450 Milan in php we have to create dropdown menu show the names coming from the database when the user choose a name from the menu will show the salary for this person . one more thing there is no sumbit button , I mean when the user choose a name from the dropdown menu will show the salary without any click. would you help to create php code and javascript if it's needed.
Computer Science please please any help ASAP Query #5: Code a query that will make use of SQL Server intrinsic functions and reference the Instructors table. Must have alias names for each column. First column: Display the instructors name as first name initial followed by a period and space and then last name such as B. Brown Second column: Display the year only for the hire date. Third column: Difference in months between today’s date and the hire date. Last column: Display the string literal ‘Full-time instructor’ if an instructor has a Status of F or return the string literal of ‘Adjunct instructor’ if they have a status of P. You can use the Case function or the IIF function.
Query 3: Write a parameter query to display the names of all prospects each member tried to recruit based on the member’s first name and the member’s last name you input. List the member’s First Name, member’s Last Name, prospect’s First Name, and prospect’s Last Name (in this order in the query grid). Display the member’s First Name Heading as Member First Name, member’s Last Name Heading as Member Last Name, prospect’s first name heading as Prospect First Name, and prospect’s last name heading as Prospect Last Name. Sort the list by Member Last Name, Member First Name, Prospect Last Name, and Prospect First Name, all ascending order. (WE ARE USING ACCESS SO I AM JUST TRYING TO UNDERSTAND WHAT TO PUT AND PLUG IN ETC. USE MY PICTURES AS REFERRENCE!)
SQL QUERIES Employees(EMPLOYEE_ID,FIRST_NAME,LAST_NAME,EMAIL,PHONE_NUMBER,HIRE_DATE,JOB_ID,SALARY,COMMISSION_PCT,MANAGER_ID,DEPARTMENT_ID)Department(DEPARTMENT_ID,DEPARTMENT_NAME,MANAGER_ID,LOCATION_ID)A: Write a query in SQL to display the minimum, maximum salary and DEPARTMENT_ID of all thosedepartments whose minimum salary is greater than 4000 in ascending order.