For the lap joint below, the maximum safe load P if the bearing stress of the plate is limited to 110 MPa is: d of each rivet = 20mm 130 mm 20 mm ø Rivets 25 mr1 mm
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strength of materials (no long explanation needed. rate will be given)
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- A spherical balloon is filled with a gas. The outer diameter of the balloon is 20 in. and the thickness is 0,012 in. Calculate the maximum permissible pressure in the balloon if the allowable tensile stress and the allowable shear stress in the balloon are 1 ksi and 0.3 ksi, respectively.If the flat link shown below has an allowable tensile stress of 75 MPa, then a force P 1800 N will require the link to have a minimum thickness of: 30 mm 10 mm 3.20 mm 2.60 mm 2.40 mm 2.20 mm 3.60 mm 3.00 mm 2.80 mm O 3.40 mmWe will use both shearing and bearing analysis to determine the quantities of rivets needed to fasten BC and BE. We can determine two values then choose what will be more safe. ■ For Member BC: ■ Based on Shearing: V T == ■ Av Based on Bearing: P Ab 70MPa = 96000 N .n. (19) ²x n 1/4. π n = 4.84 5 rivets 96000 N (19mm) (6mm) xn 140MPa n = 46.015≈ 7 rivets For member BC, we must use 7 rivets since we must need a minimum of 7 rivets to resist bearing stress produced by the connection. If we only use 5 rivets, then the bearing stress will become 168.42 MPa. It will result to failure since the allowable bearing stress is only 140 Mpa. ■ For member BE: (Practice at Home) Pac EXAMPLE: 5. The figure shows a roof truss and the detail of the riveted connection at joint B. Using allowable stresses of t = 70 MPa and ob= 140 MPa, how many 19-mm diameter rivets are required to fasten member BC to the gusset plate? Member BE? What is the largest average tensile or compressive stress in BC and BE? Say…
- The lap joint carries an P axial load of P - 50 kN. It is connected by 3-18 mm 150 mm 20 mm 20 mm dia. rivets. 38. What is the bearing stress between a plate and a rivet? 39. What is the shear stress in rivet? 40. What is the maximum average tensile stress in each plate?Two plates each with thickness of 18 mm are bolted together with 6 – 20mm ø bolts forming a lap connection. Bolt spacing are as follows: X1 = 50 mm, X2 = 120 mm and X3 = 100 mm FvRivet = 130 MPa. Calculate the the pemissible tensile load P under the following conditions. a. Based on the effective net area. b. Based on block shear. c. Based on the safe value of P.A bracket is supported by means of 4 rivets of the same size. Design the diameter of the rivet if C, (tensile ultimate stress) for the rivet material is 560MPA. Which of the rivet has max resistance? 20N 20kN 30 nm so nm 30 mm 1.
- C- ODD: Assume that the axial load P = 40KN applied to the lap joint is distributed equally among the three rivets. What is the smallest diameter of the 130 mm rivet if the allowable stresses are 90 MPa for 25 mm bearing between a plate and a rivet, and 40 25 mm MPa for shear in rivets?1-Two rivets holds three sheets of steel together, and is loaded as shown below. If the maximum average shear stress allowed for the material is 250 MPa, and factor of safety 4 is required by the design standards, find the minimum rivets diameter. 20 kN 10 kN 10 kNThe P load applied to a steel bar is transferred to the board by an annular washer. The diameter of the rod is 34mm and the inner diameter of the washer is 35.7 mm. Since it is known that the axial normal stress on the steel bar is 119 MPa, and the average bearing stress between the washer and the board should not exceed 34 MPA, how many mm is the smallest allowable outer diameter of the washer?
- s): The butt connection shown below is fastened by 20-mm diameter bolts. Find the maximum allowable load (P) that can be applied if the bearing stress, tensile stress and shearing stress is limited to 160 MPa, 80 MPa and 50 MPa, respectively. Use safety factor 1.5. P4- P4- 16 mm 50 100 50 50 100 50 40 80 40 12 mm PThe figure below shows two plates connected by two rivets. The plates are made from aluminum 6061-T6 and the rivets are made from aluminum 2014-T4. Evaluate the maximum allowable force on the connection to meet the following design criteria: (a) The shear stress in a rivet cannot exceed 14 of the ultimate strength in shear. (b) The tensile stress in the plates cannot exceed 13 of the yield strength. (c) The bearing stress on either the plates or the rivets cannot exceed the design bearing stress 9 mm 75 mm 38 mm 38 mm 12 mm dia. 9 mm1.3-2 A load of P = 3.0 kips is applied to the connection. The failure stress of the pin material is 25 ksi. Design the diameter of the pin to the nearest 1/16-inch assuming a factor of safety of 2.