For the initially uncharged circuit to the right, v₁(t) = 10sin(t) Volts and will be applied to the circuit starting at t=0 (i.e., when the switch is closed). Using Laplace Transform, provide the following: t=0 VIN (t) 100mH 1. Transfer function of the circuit, H(s) = Vo(S)/V₁N(S) 2. Expanded frequency-domain equation of the output voltage, Vo(s) (i.e., the equation found after partial fraction expansion) 3. Simplified time-domain equation of vo(t) from the inverse Laplace Transform of Vo(s) 5Ω -vo(t)

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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For the initially uncharged circuit to the right, Vin(t) = 10sin(t) Volts
and will be applied to the circuit starting at t=0 (i.e., when the switch
is closed). Using Laplace Transform, provide the following:
t=0
~) v (t)
V
100mH
1. Transfer function of the circuit, H(s) = Vo(S)/Vin (S)
2. Expanded frequency-domain equation of the output voltage,
Vo(s) (i.e., the equation found after partial fraction expansion)
3. Simplified time-domain equation of vo(t) from the inverse Laplace Transform of Vo(s)
5Q2
+
vo(t)
Transcribed Image Text:For the initially uncharged circuit to the right, Vin(t) = 10sin(t) Volts and will be applied to the circuit starting at t=0 (i.e., when the switch is closed). Using Laplace Transform, provide the following: t=0 ~) v (t) V 100mH 1. Transfer function of the circuit, H(s) = Vo(S)/Vin (S) 2. Expanded frequency-domain equation of the output voltage, Vo(s) (i.e., the equation found after partial fraction expansion) 3. Simplified time-domain equation of vo(t) from the inverse Laplace Transform of Vo(s) 5Q2 + vo(t)
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