For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population. The word counts of five essays are 508, 634, 545, 611, and 577. Use a sample size of 2. O The mean of the population is 575. (Round to two decimal places as needed.) The standard deviation of the population is 45.10 (Round to two decimal places as needed.) Identify all samples of size 2 with the correct accompanying means below. O A. 508, 611, x= 559.5 O B. 634, 508, x 571 O C. 611, 634, x= 622.5 O D. 577, 508, x 542.5 O E. 611, 611, x=611 O F. 508, 545, x = 526.5 O G. 545, 577, x = 561 O H. 577, 624, x = 600.5 O1. 545, 508, x = 526.5 O J. 545, 634, x = 589.5 O K. 577, 545, x = 561 O L. 634, 611, x= 622.5 O M. 577, 611, x 594 O N. 611, 577, x = 594 O 0. 611, 545, x = 578 O P. 545, 611, x 578 O Q. 611, 508, x = 559.5 OR. 611, 634, x = 548 O S. 545, 545, x = 545 O T. 508, 508, x = 508 O U. 634, 634, x = 634 OV. 577, 577, x= 577 O W. 634, 545, x = 589.5 O X. 634, 577, x = 605.5 OY. 508, 634, x 571 O Z. 508, 577, x = 542.5 O. 577, 634, x = 605.5 Get more help - Clear all Check answer

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For the following situation, find the mean and standard deviation of the population. List all samples (with
replacement) of the given size from that population and find the mean of each. Find the mean and standard
deviation of the sampling distribution and compare them with the mean and standard deviation of the population.
The word counts of five essays are 508, 634, 545, 611, and 577. Use a sample size of 2. O
The mean of the population is 575
(Round to two decimal places as needed.)
The standard deviation of the population is 45.10.
(Round to two decimal places as needed.)
Identify all samples of size 2 with the correct accompanying means below.
O A. 508, 611, x = 559.5
O B. 634, 508, x = 571
OC. 611, 634, x = 622.5
O D. 577, 508, x = 542.5
O E. 611, 611, x = 611
OF.
508, 545, x = 526.5
OG. 545, 577, x = 561
O H. 577, 624, x = 600.5
O I.
545, 508, x = 526.5
J. 545, 634, x = 589.5
K. 577, 545, x = 561
O L. 634, 611, x = 622.5
O M. 577, 611, x= 594
O N. 611, 577, x = 594
O O. 611, 545, x = 578
O P. 545, 611, x= 578
O Q. 611, 508, x = 559.5
O R. 611, 634, x = 548
O S. 545, 545, x = 545
O T. 508, 508, x = 508
O U. 634, 634, x = 634
O W. 634, 545, x= 589.5
O X. 634, 577, x = 605.5
OV. 577, 577, x = 577
OY. 508, 634, x= 571
O Z. 508, 577, x = 542.5
577, 634, x = 605.5
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Transcribed Image Text:For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population. The word counts of five essays are 508, 634, 545, 611, and 577. Use a sample size of 2. O The mean of the population is 575 (Round to two decimal places as needed.) The standard deviation of the population is 45.10. (Round to two decimal places as needed.) Identify all samples of size 2 with the correct accompanying means below. O A. 508, 611, x = 559.5 O B. 634, 508, x = 571 OC. 611, 634, x = 622.5 O D. 577, 508, x = 542.5 O E. 611, 611, x = 611 OF. 508, 545, x = 526.5 OG. 545, 577, x = 561 O H. 577, 624, x = 600.5 O I. 545, 508, x = 526.5 J. 545, 634, x = 589.5 K. 577, 545, x = 561 O L. 634, 611, x = 622.5 O M. 577, 611, x= 594 O N. 611, 577, x = 594 O O. 611, 545, x = 578 O P. 545, 611, x= 578 O Q. 611, 508, x = 559.5 O R. 611, 634, x = 548 O S. 545, 545, x = 545 O T. 508, 508, x = 508 O U. 634, 634, x = 634 O W. 634, 545, x= 589.5 O X. 634, 577, x = 605.5 OV. 577, 577, x = 577 OY. 508, 634, x= 571 O Z. 508, 577, x = 542.5 577, 634, x = 605.5 Get more help - Clear all Check answer L.
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