a) Balance under acidic conditions H3ASO3(aq) + 12 (aq)-> H3ASO4 (aq) + I^- B) Balance under basic conditions Cu(OH)2 (s) + N2H4(aq) > Cu(s) +N2(g)

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Balancing Chemical Equations:**

**A) Under Acidic Conditions:**

Given Chemical Equation:
\[ \text{H}_3\text{AsO}_3\text{(aq)} + \text{I}_2\text{(aq)} \rightarrow \text{H}_3\text{AsO}_4\text{(aq)} + \text{I}^- \]

Steps to Balance:
1. **Identify the oxidation and reduction components.**
2. **Balance the equation for atoms and charge using H\(^+\) for acids.**

**B) Under Basic Conditions:**

Given Chemical Equation:
\[ \text{Cu(OH)}_2\text{(s)} + \text{N}_2\text{H}_4\text{(aq)} \rightarrow \text{Cu(s)} + \text{N}_2\text{(g)} \]

Steps to Balance:
1. **Separate the reaction into half-reactions.**
2. **Balance atoms and charge using OH\(^-\) for bases.**

**Note:** The balancing process involves ensuring that the number of atoms for each element and the charges are equal on both sides of the equation.
Transcribed Image Text:**Balancing Chemical Equations:** **A) Under Acidic Conditions:** Given Chemical Equation: \[ \text{H}_3\text{AsO}_3\text{(aq)} + \text{I}_2\text{(aq)} \rightarrow \text{H}_3\text{AsO}_4\text{(aq)} + \text{I}^- \] Steps to Balance: 1. **Identify the oxidation and reduction components.** 2. **Balance the equation for atoms and charge using H\(^+\) for acids.** **B) Under Basic Conditions:** Given Chemical Equation: \[ \text{Cu(OH)}_2\text{(s)} + \text{N}_2\text{H}_4\text{(aq)} \rightarrow \text{Cu(s)} + \text{N}_2\text{(g)} \] Steps to Balance: 1. **Separate the reaction into half-reactions.** 2. **Balance atoms and charge using OH\(^-\) for bases.** **Note:** The balancing process involves ensuring that the number of atoms for each element and the charges are equal on both sides of the equation.
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For the first problem, shouldnt it only be e^-1 instead of 2e^-1?

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