for the circust below at time t=0 it Changes from a to b Determine the auvent expression far the inductor enegy discipated by the 10s2 vesistor at +70 In what time (+) it will disapate 90 f of the storeged energy The 10 a 10 A t= 0 100 mH 10 Ω
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A: The solution is given below
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A: The solution can be achieved as follows.
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A: Note: As per the company policy, we experts are allowed to answer only one question. Kindly post the…
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Q: Q1) For the circuit in Fig. (1), find the inductor voltage for t>0. RI t= 0 R: Fig (1) ww
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- You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.The figure below shows a simple RC circuit with a 3.30-μF capacitor, a 4.40-M resistor, a 9.00-V emf, and a switch. What are the following exactly 9.00 s after the switch is closed? (a) the charge on the capacitor 13.7204 UC (b) the current in the resistor 0.0110522 x Your response is off by a multiple of ten. HA (c) the rate at which the capacitor is storing energy μW (d) the rate at which the battery is delivering energy μWIn the following figure, the switch is left in position a for a long time interval and is then quickly thrown to position b. Find and rank the magnitudes of the voltages (V, VL, VRI, Vr2) across the four circuit elements a short time thereafter from the largest to the smallest. Vs 12.0 V 2.00 H 1 200 0 VRI 12.0 0 Vr2
- For the circuit below with input voltage V1, a step function of magnitude 25 volts at time t-0, find the transient response voltage across the capacitor C1 and plot the results: (Provide your calculations and reasoning for your answer.) R1 555 250mH V1 = 0 V2 - 25 TD = 0 TR In V1 C1 TF in PW- 25 PER = 3.3uThe peak time for the first overshoot in the figure is : C(t) 1. 28 1 step input 3 secInitially relaxed series RLC circuit with R = 150 £2, L=30 H and C= 10 F has de voltage of 150 V applied at time t = 0. Find the equation for current and voltages across different elements. Also draw the waveform under different cases. E R i L -00000 C
- A resistor and a capacitance are connected in series to an emf source. The time constant of the circuit is 0.87 s. What will be the 35 - time constant of the new circuit when another capacitor identical to the first is connected in series with the circuit? O a) 0.973s O B) 1,742 s O C) 2.034 s O D) 2.136 s O TO) 0.435 sMake a clamper circuit using 500 µF capacitor, silicon diode, and a 100 KΩ resistor connected to a 10 Vpeak sine wave. Draw the output waveform and indicate the amplitude and the time values supported by your solutions. Do these for both positive and negative clamper circuit. Show your circuits first before your solutions and waveforms.Asap
- A voltage source of 10V is connected to a load through a switch.The load is a combination of a resistor of 5Ω and an inductor of 2mH in series.The inductor has no current when the switch is closed. a. What is the voltage across the resistor at t = 0? What is the voltageacross the inductor then?b. Can you see that the current through the inductor goes up with time?Does the voltage across the resistor go up with time? What happens tothe voltage across the inductor over time?c. Does the inductor current have an upper limit? Thank you for your help.The figure below shows a simple RC circuit with a 3.50-µF capacitor, a 3.60-MQ resistor, a 9.00-V emf, and a switch. What are the following exactly 6.50 s after the switch is closed? S C R (a) the charge on the capacitor (b) the current in the resistor µA (c) the rate at which the capacitor is storing energy (d) the rate at which the battery is delivering energyConsider the circuit shown below, with an initially uncharged capacitor C and two identical resistors R. R O www V I C I₂ R C R At the instant the switch is closed, the current through the capacitor will be: zero At the instant the switch is closed, the current through the right-side resistor will be: V/R, directed Up After the switch has been closed for a very long time, it is opened. The current through the right-side resistor will be V/R, directed Down The switch is closed at t = 0. At t = ~ (long after) the current through the right-side resistor will be: V/2R, directed Down ✓ The switch is closed at t = 0. At t = ~ (long after) the current through the capacitor will be: V/2R, directed Up After the switch has been closed for a very long time, it is ope ed. The current through the be? V/R, directed Down pacitor will