For the circuit shown ,IC2 = 1mA ,VCE1 = 2V , and VCE2 = 5V1. The value of RC is equal to• ohm2. The value of R1 is equal to수 |ohm3. The value of R2 is equal to수 |ohm+15VRCR1Q2B1 = B2 =100R2Q1100KO For the amplifier shown in Fig.(2) , find the value of RE and RC so thatIE = 0.93mA , and Av = Vo/Vs = 120.Assume the transistor has ß = 100, and VT =26mV.Please write your name and ID atthe top of the answer sheet-10VRC50μVo(t)5OKN100uFREuslt)Fig.(2)+10V

Answered: Image /qna-images/answer/9c04ceb0-a730-4d0f-a987-c4adf4772d2d.jpg

For the circuit shown ,IC2 = 1mA ,VCE1 = 2V , and VCE2 = 5V 1. The value of RC is equal to 수 |ohm 수 | ohm 2. The value of R1 is equal to 수 ohm 3. The value of R2 is equal to +15V RC R1 02 B1= B2 =100 R2 Q1 100KO

For the circuit shown ,IC2 = 1mA ,VCE1 = 2V , and VCE2 = 5V 1. The value of RC is equal to 수 |ohm 수 | ohm 2. The value of R1 is equal to 수 ohm 3. The value of R2 is equal to +15V RC R1 02 B1= B2 =100 R2 Q1 100KO

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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KVL and KCL

KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.

Sign Convention

Science and technology incorporate some ideas and techniques of their own to understand a system skilfully and easily. These techniques are called conventions. For example: Sign conventions of mirrors are used to understand the phenomenon of reflection and refraction in an easier way.

Question

For the circuit shown ,IC2 = 1mA ,VCE1 = 2V , and VCE2 = 5V
1. The value of RC is equal to
• ohm
2. The value of R1 is equal to
수 |ohm
3. The value of R2 is equal to
수 |ohm
+15V
RC
R1
Q2
B1 = B2 =100
R2
Q1
100KO

For the amplifier shown in Fig.(2) , find the value of RE and RC so that
IE = 0.93mA , and Av = Vo/Vs = 120.
Assume the transistor has ß = 100, and VT =26mV.Please write your name and ID at
the top of the answer sheet
-10V
RC
50μ
Vo(t)
5OKN
100uF
RE
uslt)
Fig.(2)
+10V

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