For the circuit shown find the impedance phase angle Z (in degrees) i = 0.02 sin(157t+40) V=2547.4 sin(157t-50) O Z
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A: I have written this solution as handwritten solution. Hope you find the perfect solution.
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A: It is given that: ZL=8+j6 Ω
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Q: Initially uncharged four capacitors are connected as shown in the Figure. Here, V₁ = 38,4 V, V₁ =…
A: Va = 38.4 VVb = 17.2 VC1 = 14 μFC2 = 35 μFC3 = 28 μF C4 = 7 μF
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A: S=10∠26.56° VAf = 50 HzR = 2 ohm Pactive= 10cos26.56° P = 8.94 Watt Xreactive=…
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Q: solve part b
A: As asked in the problem, part b is being solved here. Given: A network, To find: Current I0.
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A: Circuit diagram
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- A 220 Ω resistor is in series with an 80 mH inductor. The AC source is 48 at 1 kHz. The power factor is ________. Hint: Draw the circuit and get Vs and IsTwo impedances Z1 = 2+j6 N and Z2 = 6-j12 Q are connected in series. What is the resultant impedance in the polar form? 10cis-36.9° O 10cis36.9° 10cis53.1° 10cis-53.1°QUESTION 4 A resistor, a capacitor, and an inductor are connected in series with a function generator. The resistor has a resistance of 1.5k2, the inductor has a reactance of 1.2kQ, and the capacitor has a reactance of 2002. The circuit has a total current of 172mA RMS. Find the total voltage. O 310V233.7 O 74.5VL-14° 188V273.2 O 44.4VL-25.3°
- 2. A series RL circuit has voltage and current equations of e = 141.42 sin 2n30t + 141.42 sin 2n90t volts and i = 9.8 sin (2n30t - 30°) + 5.66 sin (2n90t - 60°) amperes. Determine the inductance L. A. 92.5 mH B. 38.3 mH C. 27.22 mH D. 83.49 mHProb. I and Vc For the following RMS phasor circuit, a coworker has determined values for 50 Ohms 50 Ohms i,- 225 2253.13° = 190.92 + 254.56 VRMS R1 + R2 Vc = 237.17/26.565° = 212.13+ 106.07 VRMS 100 2 -3Z98.13° =-0.4243 + J2.970 ARMS C -j60 Ohms For this problem provide at least 3 digits of precision for the answers. The results for the following calculations are to be answered in - a) Find the current I b) Determine the real (P) and reactive(Q) power DELIVERED by the source c) Determine the real (P) and reactive (Q) power ABSORBED by each impedance ( resistors R1 and R2, inductor and capacitor). The values for P and Q can be positive or negative. Remember S =P+jQ, so do not include the j with your answer for Q. Each of these answers will require two parts. For the phasor a magnitude and angle will be needed. For the powers, The real power P and the reactive power Q are required.A load is rated at 440V(rms), 7.5A(rms) and 3.3KW when connected to a 50HZ source. Find the load impedance.
- R An RC parallel circuit. A 110-V, 60.0-Hz, AC line is connected in parallel to a resistor of 1000 Q and a capacitor of 1.00 μF, as shown in figure above. Find The capacitive reactance is must nearly. 2650 j2 0-2650 j 0-60 j 60jQQUESTION 5 A resistor, a capacitor, an inductor, and a mystery component are connected in parallel. The resistor has a resistance of 300N, the capacitor has a reactance of 2500, and the inductor has a reactance of 6000. The total impedance of the circuit is 59.52-j119.640. What is the mystery component? O there is no mystery component O resistor O inductor O capacitorTwo impedances of Z = 100 +j50 Q and Z2 = 20 -j20 Q are connected in series. what is the magnitude of the equivalent impedance in 2? %3D %3D Your Answer: Answer
- A 15ohms resistor connected in parallel with an impedance of 8 - j2 across an AC source. The entire circuit takes a total average power of 2000 watts. What is the average power in the 15ohms resistor?ESSAY: Describe what happens to the power in this RLC series circuit as the capacitance decreases. Explain in general terms why the observed change should occur. Understand the effects of basic electrical components on the average power of the system and the concept of power factor. Differentiate between average power and real power.A series circuit has 50 ohm resistance, 2.22 microfarad capacitance and inductance of 8 mH. Find the total impedance at 796 Hz frequency. a. 50-j150 b. 50+j50 c. 50-j50 d. 50+j130