For the circuit below, determine the diode voltages VD1 and Vp2, diode currents Ip1 and Ip2, and voltage across the resistor, VRLIMIT- Use ideal model. *Use 4 decimal places. Assume r'a (for both diodes)=200. Note D, is Germanium, D2 is Silicon, VBIAS = 14V and RLIMIT = 760 ohms . VD1 = Blank 1 V; VD2 = Blank 2 V; Ip1 = Blank 3 mA; Ip2 = Blank 4 mA ; VRLIMIT = Blank 5 V ... Capture3.JPG +VD1- +VRLIMIT +V02- Io2 V BIAS

One component that does not need to be installed in the correct orientation is a: a. Resistorb. Diodec. Voltage regulatord.

Choose the doping material that will cause silicon to become a p-type semiconductor. A. Ge B. As C. Te D. B

Assuming an ideal diode model for all the diodes in the circuit below, chose the correct state (bias) for each diode. R1 ww 9kQ 1N1199C R2 D1 18kQ 1N1199C V2 12 V R3 1kQ D3 1N1199C R4 D3: On (Forward Bais) D3: Off (Reverse Bais)

For the circuit in the figure, let V input = 8V, Ri = 12ohms, RL = 10ohms, and VZ = 3.3V. Determine the voltages and currents of the resistors and the current of the zener diode.

For the diode circuit shown below, an IN4007 diode is used, and is connected to a variable voltage supply (VIN) that provides a maximum output voltage of 6 V. The 1N4007 diode has absolute maximum forward current rating of 1A, and can be modelled with a diode drop of 0.7 V. What is the minimum value of resistance (R1) you can use to avoid damage to the diode? Answer: Vin ww R1 O Vout

a) What is n-type semiconductor materials? What are the majority and the minority cariers? b) What is p-type semiconductor materials? What are the majority and the minority cariers? c) What is depletion region of a p-n junction diode? d) Describe in your own words the forward-bias and reverse- bias conditions of a p-n junction diode. e) Draw a Diode Symbol and label the anode and the cathode. Si Ge 2 ka f) Find V, in the circuit shown in +20 V 2 k2 15V Fig. Fuad Al-Mannai EENG261 Page 1

Answr all the questions one by one and solve all the unknown values giving all the correct details Let the last digit of the ID = 9