Refer to the table of equations when answering. For the cantilever beam with shown loading, determine the deflection at the freeend. (E = 200 GPa;1 = 26.9 x 104 mm*)kN40AB5 m Table of EquationsLoading ConfigurationDeflectionBPxAy ==ZR:(x- 3L)6EI(Px2(x – 3a) 0 sIsa6EIРа?A (a - 3x) asxSLy =-6EIWoBA.y =:24EI24ET (-612 + 4Lx - x2)L.Luduing ContigurationDeflectionWoB(Wox?ZAE (-6a? + 4ax - x) 0s xsa24EIAy =W,a24E (a - 4x)asxSLWoWex?120LEI-10L + 10Lx – 5Lx + x)BAy =120LEIL.BPxy =48EI;(4x² – 31²) 0sxs;Pbx61. ET -L + x² + b²)lEL ET(*- a) - (L² – b²)x + x* asxsLBOSxsaAy =PbL.Woy =y =AR(-L' + 2Lx? - x)24EImimyB¡|-a²(a – 21.)² – 2a(a – 21.)x² – Lx*] 0sIsa24L EIWea?241 EI (L- x)(a² – 4Lx + 2x?)asxSL24L EIWoy = 360L EI-7L + 10L?x2 – 3x*)

To find : The deflection of beam at the free end beam. Given: The moment of inertia is I=26.9×106…

Answered: For the cantilever beam with shown…

For the cantilever beam with shown loading, determine the deflection at the free end. (E = 200 GPa; 1 = 26.9 x 106 mm¹) "1 A 5 m B 40 kN m x

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

Refer to the table of equations when answering.

For the cantilever beam with shown loading, determine the deflection at the free
end. (E = 200 GPa;1 = 26.9 x 104 mm*)
kN
40
A
B
5 m

Table of Equations
Loading Configuration
Deflection
B
Px
A
y =
=ZR
:(x- 3L)
6EI
(Px2
(x – 3a) 0 sIsa
6EI
Ра?
A (a - 3x) asxSL
y =
-6EI
Wo
B
A.
y =:
24EI
24ET (-612 + 4Lx - x2)
L.
Luduing Contiguration
Deflection
Wo
B
(Wox?
ZAE (-6a? + 4ax - x) 0s xsa
24EI
A
y =
W,a
24E (a - 4x)
asxSL
Wo
Wex?
120LEI-10L + 10Lx – 5Lx + x)
B
A
y =
120LEI
L.
B
Px
y =
48EI
;(4x² – 31²) 0sxs;
Pbx
61. ET -L + x² + b²)
lEL ET(*- a) - (L² – b²)x + x* asxsL
B
OSxsa
A
y =
Pb
L.
Wo
y =
y =AR(-L' + 2Lx? - x)
24EI
mim
y
B
¡|-a²(a – 21.)² – 2a(a – 21.)x² – Lx*] 0sIsa
24L EI
Wea?
241 EI (L- x)(a² – 4Lx + 2x?)
asxSL
24L EI
Wo
y = 360L EI-7L + 10L?x2 – 3x*)

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