For general projectile motion, when the projectile is at the highest point of its trajectory its velocity is perpendicular to the acceleration. its acceleration is zero. the horizontal component of its velocity is zero. the horizontal and vertical components of its velocity are zero. its velocity and acceleration are both zero.
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A: The answer is below
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- The marble is projected horizontally. If the initial velocity is Vo, what are the marbles initial vertical and horizontal components of the velocity?The projectile is launched with a velocity vo. Determine the range R, the maximum height h attained, and the time of flight. Express the results in terms of the angle 0 and vo. The acceleration due to gravity is g. y R- Neglecting the size of the ball, determine the magnitude vA of the basketball's initial velocity and its velocity when it passes through the basket.An artilery sheill is fired with an Initial velocityY of 300 m/s at 45.0° above the horizontal. To clear an avalanche, it explodes on a mountalnside 41.5 s after firing. What are the x- and y-coordinates of the shetl where it xplotes, relative to its firing point? in tn Etn Arwer
- A monkey is sitting at the top of a tree 20 m above ground level. A person standing on the ground wants to feed the monkey. He uses a bow and arrow to launch the food to the monkey. If the person knows that the monkey is going to drop from the tree at the same instant that the person launches the food, how should the person aim the arrow containing the food? Air resistance is small enough to be ignored. O He should aim it at the monkey. O He should aim it below the monkey. O He should aim it above the monkey.Given, position vector of a particle, r(t) = 2t i. Which of the following statements is/are true? All of the above. Magnitude of acceleration is linearly proportional to t. The speed of the particle varies with the time linearly. Direction of velocity changes with the O time but direction of acceleration does not change with the time.. Prove that the trajectory of a projectile is parabolic, havingthe form y = ax + bx2. To obtain this expression, solve theequation x = v0xt for t and substitute it into the expressionfor y = v0yt – (1 / 2)gt2(These equations describe the xand y positions of a projectile that starts at the origin.) Youshould obtain an equation of the form y = ax + bx2 wherea and b are constants
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- You are really angry at your family, and in your frustration you decide you are going tothrow the pizza you bought for dinner onto the roof of your house. You are 6 metersfrom the house and the roof of the house is 3 meters above the ground. Assuming youtoss the pizza from ground level with an initial speed of 10 m/s at an angle of 60° (abovethe horizontal), how far onto the roof does the pizza land? Assume the roof is flat. Giveyour answer to 2 significant figuresA cannon ball is fired with an initial velocity vo at a wall that is 100. meters tall and located 450. meters away. The initial angle of launch of the cannon ball is 0. We want to determine if the cannon ball will clear the wall. If not how high-up will the ball strike the wall from the ground. (A) Sketch a graph showing position of the cannonball during its flight (y versus x) showing and labeling the initial velocity vector. Identify and write knowns and unknowns (B) Without using numerical values, determine which physics equations of motion will help solve this problem. Simplify as useful for this particular case. (C) If the initial horizontal component of the balls velocity is 90.0 m/s and its initial angle is 0-24 degrees, does the cannonball clear the wall? If not, how high above the ground is the ball when it hits the wall?cuit PROJECTILE MOTION A. A cannonball is shot horizontally at 20 m/s on top of a 50 m cliff. (a) How far horizontally from the cliff does the cannonball land on the ground? (b) What was the final velocity of the cannonball before hitting the ground? В. A ball is launched from the ground at an angle of 53° above the horizontal at 10 m/s. The ball returns to the ground. (a) How far did the ball go horizontally? (b) How far vertically is the peak? C. A tennis ball is hit with an initial velocity of 25 m/s [10° above the horizontal] starting from a height of 2.1 m, and lands on the ground. There is a net 1.4 m high. (a) What is the height above the ground at the peak? (b) If the ball clears the net at its peak, how much will it be above the net?