For each listed phenotype you are to list the correct genotype Straight hair (S) is dominant to curly hair (s). Homozygous straight Heterozygous straight Curly Roundheads (R) are dominant to square (r) Homozygous round Heterozygous round Square
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For each listed
Straight hair (S) is dominant to curly hair (s).
Homozygous straight
Heterozygous straight
Curly
Roundheads (R) are dominant to square (r)
Homozygous round
Heterozygous round
Square
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- Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口In humans, a widow’s peak hairline (H) has complete dominance over the straight hairline (h).What is the genotype for an individual that homozygous dominant for this traitman, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly hair (w). Cross a marriage between a heterozygous spotted, non-wooly man with a heterozygous wooly-haired, non-spotted woman. Give the genotypes and phenotype of offspring.
- A phenotypic ratio of 6:6:4 is possible between a male who is heterozygous free earlobes and heterozygous freckles, and a female who is homozygous free earlobes and heterozygous. The genotype of the female is written this way Eeff. Key: E = free earlobes e = attached earlobes F = freckles f = no freckles O If both statements are FALSE If both statements are TRUE O If the first statement is FALSE and the second statement is TRUE O If the first statement is TRUE and the second statement is FALSEWhich of the Pedigree Diagrams above is most likely to show a family with Achondroplasia? A KEY Homozygous Homozygous Heterozygous Heterozygous Wild Type Male Female Male Female Male с. Note: Completely red symbol denotes an individual exhibiting the phenotype of interest 11 IV V 1/4 1/2 1/2 ₂₂( 1/2 1/2 5 1/4 Wild Type Female 1/2 B Affected Known carrier Affected female Normal female Affected male Normal male DFor number 15-24. In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly hair (w). Cross a heterozygous parent (SsWw) with a heterozygous parent (Ssww) Give genotypic and phenotypic ratios of offspring. 15-18. What is the probability of producing spotted skin with non-wooly hair? 8/16 4/16 3/16 6/16 8/16 A. B. C. D. E. 19-21. What is the probability of producing non-spotted skin with non-wooly hair? A 2/16 B. 4/16 C. 1/16 D. 6/16 22-24. What is the probability of producing non-spotted skin with wooly hair? A 3/16 В. 4/16 с. 1/16 D. 9/16 E. 8/16
- In addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry. What is the phenotype of the male parent? What is the phenotype of the female parent? Give the phenotypic ratio expected among male children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio. Give the phenotypic ratio expected among female children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.к, х Ааv AdBbCc AaBbCc No Spacing AaBbCc 三、相、 1 Normal Heading 1 Font Paragraph 6. Let's assume that the non-taster, daughter in question 5 is a carrier of the albino trait. She marries a Styles taster man, normally pigmented, whose mother was a non-taster albino. Show the cross between these parents. Genotype of the woman Genotype of the man Genotypes Phenotypes What is the chance that their child will be a taster? Footer What is the chance that their child will be albino? What is the chance that their child will be a taster albino? J.S.)Here are the progeny of this cross: (Note that the categories are not in any particular order.)Fly type # of prog. Phenotype symbols Categorywt eyes black body wt wings 97 grn+ blk crv+Green eyes black body curved wings 709 ParentalGreen eyes wt body wt wings 9Green eyes black body wt wings 162wt eyes wt body wt wings 727wt eyes black body curved wings 12wt eyes wt body curved wings 179Green eyes wt body curved wings 105Total = 2000 9.) Write the phenotype symbols in the right-hand column. The first one has been done for you.10.) Next to that, label all fly categories as parental (NCOs), SCOs, and DCOs. One has been donefor you.11.) After each SCO/DCO label, write which gene got “unlinked” in these offspring.12.) Put these three genes into a genetic map in the proper order.13.) Calculate the genetic distance between the genes and label the map with these distances.14.) Calculate the cross-over interference15.) Return to questions #1-6 above. For question 6, you gave your opinion, but…
- Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?A woman homozygous dominant for albinism marries a man who is homozygous recessive for albinism. What are the possible genotypes and phenotypes percentages for their offspring?In humans, long eyelashes (L) are dominant to short eyelashes (I). On the left are three boxes, each containing one possible genotype for eyelash length. Match the terms/phrases on the right with their correct genotype(s); some labels may be used more than once, and some labels may not be used at all. LL LI = 11 All offspring will have long eyelashes when crossed with LI genotype Homozygous recessive Will have long eyelashes Homozygous dominant Hemizygous Heterozygous Will have short eyelashes All offspring will have medium-length eyelashes