Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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Purple Hair is dominant. Blue hair is recessive. One parent is heterozygous; the other parent has blue hair.
A.) What is the probability of them having a blue-haired child?
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- Demonstrate how males are at an increased risk of sex-linked recessive traits by crossing a female who is a carrier for Hunter syndrome with a normal male. The genotypes involved are XH, Xh, and Y. State the genotypes and phenotypes of the offspring.arrow_forwardin earlobes, attached (A) earlobe is dominant while free (f) earlobe is recessive. - free earlobes with heterozygous dominant for attached earlobes? (percent) - heterozygous for attached earlobes with heterozygous for attached earlobes. (percentage) - Homozygous dominant for attached earlobes with free earlobes. (Answer in percent)arrow_forwardDoing genetic analysis it is determined that two parents are heterozygous for two separate unlinked recessive traits (i.e., both parents are heterozygous for both loci). Given this genetic information, what is the probability of their having a child which is homozygous recessive for both traits?arrow_forward
- Colorblindness is an X linked gene. Normal vision (XN ) is dominant over colorblind (Xn). Cross a carrier female to a normal male. How many of their children will be colorblind? How many of their sons will be colorblind? How many of their daughters will be colorblind?arrow_forwardA1) The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and is heterozygous for hitchhikers thumb. What fraction of this couples children should have a widow's peak and a hitchhiker's thumb? 3/8 1/4 1/2 3/4 0 A2)The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and has no hitchhikers thumb. What fraction of this couple's children should have no widow's peak and a hitchhiker's thumb? 3/8 0 1/4 1/2 1/8arrow_forwardBrown eyes are dominant over blue eyes. This is NOT a sex linked trait. Cross a brown eyed Color blind male (whose mother had blue eyes) with a normal blue eyed female (whose father was colorblind)arrow_forward
- In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non‑freckled, normal visioned girl or a non-freckled, normal visioned boy? What is the probability that the first four children born to the couple will be freckled and normal visioned girls?arrow_forwardWidow's peak is dominant to straight hair line. What is the chance of producing a child with a straight hair line from parents that one is homozygous dominant and the other is homozygous recessive? 0% (no chance) 100% (4 out of 4) 75% (3 out of 4) 25% (1 out of 4) 50% (2 out of 4)arrow_forwardColorblindness is an X-linked recessive trait. The an has normal vision and the woman is colorblind. What is the probability that their daughters will be colorblind? 75%, 25%, 100%, 0%, or 50%?arrow_forward
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