For an ideal boost converter, derive the value for Loritical in terms of duty cycle, switching frequency, and load, at the boundary discontinues current mode and continuous current mode. Vin Q, R to

Q 3. The single-phase half-wave rectifier is supplied directly from a 120-V (rms), 60-Hz source through a step-down transformer with turns ration 10 : 1. The load resistance RL, is 10 N. Determine (a) the average output voltageVolav), (b) the average load current I(av), (c) the rms load voltage Volrms), (d) the rms load current I(rms), (e) the ripple factor RF of the output voltage, (f) the rms ripple voltage Vr(rms), (g) the average diode current Ip(av), (h) the rms diode current Ip(rms), (i) the peak inverse voltage PIV of the diode, (j) the average output power Po(AC), (k) the DC output power Po(DC), and (I) the frequency fr of the output ripple voltage. (

5. For the transformer coupled half- wave rectifier circuit shown below: detei peak secondary voltage of the transformer 4:1 120V, 60H3 R. 2.5KL

In the full-wave rectifier circuit of figure, the transformer has a turns ratio of 1:2. The transformer primary winding is connected across an AC source of 230V (rms), 50 Hz. The load resistor is 50ohms. For this circuit, determine the peak-to- peak ripple in the output voltage * Di i v2 = VmSin ot RL Vs(N V1 Vo + V3 = VmSin ot D2 Full-wave rectifier- Circuit operation during positive half cycle 460 V 207 V 325.3 V None of the above ell ell

Subject : Power electronics Please write handwritten Answer