For a study conducted by the research department of a pharmaceutical company, 205 randomly selected individuals were asked to report the amount of money they spend annually on prescription allergy relief medication. The sample mean was found to be $17.60 with a standard deviation of $5.30. A random sample of 250 individuals was selected independently of the first sample. These individuals reported their annual spending on non-prescription allergy relief medication. The mean of the second sample was found to be $18.40 with a standard deviation of $4.20. As the sample sizes were quite large, it was assumed that the respective population standard deviations of the spending for prescription and non-prescription allergy relief medication could be estimated as the respective sample standard deviation values given above. Construct a 95% confidence interval for the difference between the mean spending on prescription allergy relief medication (₁) and the mean spending on non-prescription allergy relief medication (₂). Then find the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to at least two decimal places. (If necessary, consult a list of formulas.) Lower limit: X Ś Upper limit:

A Statistics instructor wanted to compare the scores on the same final exam given to students at a local community college and local university.  The Statistics instructor feels that students at the community college would be better prepared and have higher exam scores on the final exam. After grading the final exams from both institutions, the Statistics instructor found that for a sample of 36 community college students, the sample had a mean score of 84 with a standard deviation of 3.4.  A sample of 45 university students had a mean score 79 with a standard deviation of 2.6.  Construct a 95% confidence interval for the difference between population mean exam scores. Round your final results to one decimal place.      _____________     ≤      ???  −  ?????      ≤     ______________

For a study conducted by the research department of a pharmaceutical company, 235 randomly selected individuals were asked to report the amount of money they spend annually on prescription allergy relief medication. The sample mean was found to be $17.80 with a standard deviation of $4.30 . A random sample of 250 individuals was selected independently of the first sample. These individuals reported their annual spending on non-prescription allergy relief medication. The mean of the second sample was found to be $18.20 with a standard deviation of $4.00 . As the sample sizes were quite large, it was assumed that the respective population standard deviations of the spending for prescription and non-prescription allergy relief medication could be estimated as the respective sample standard deviation values given above. Construct a 90% confidence interval for the difference −μ1μ2 between the mean spending on prescription allergy relief medication ( μ1 ) and the mean…

A published study says that 95 percent of American children are vaccinated against measles, with a standard deviation of 1.5 percent. You draw a sample of 100 children from your community and check their vaccination records, to see if the vaccination rate in your community is the same as the nationalaverage. What distribution will you use for this test, and why?

A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering cholesterol levels. It believes that people who take Praxor will average a greater decrease in cholesterol level than people taking a placebo. After the experiment is complete, the researchers find that the 38 participants in the treatment group lowered their cholesterol levels by a mean of 23.2 points with a standard deviation of 4.4 points. The 44 participants in the control group lowered their cholesterol levels by a mean of 21.5 points with a standard deviation of 2.9 points. Assume that the population variances are not equal and test the company's claim at the 0.01 level. Let the treatment group be Population 1 and let the control group be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.

One year Perry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 2.57. Also, Rita had the lowest ERA of any female pitcher at the school with an ERA of 3.26. For the males, the mean ERA was 4.304 and the standard deviation was 0.894. For the females, the mean ERA was 4.158 and the standard deviation was 0.519. Find their respective z-scores. Which player had the better year relative to their peers, Perry or Rita? (Note: In general, the lower the ERA, the better the pitcher.) Perry had an ERA with a z-score of Rita had an ERA with a z-score of (Round to two decimal places as needed.) Textbook Get more help - $ 1 G Search or type URL % 31 6 & 7 * 8 + ( 9 0 Clear all + Check answer delete

According to the U.S. Census, the average adult woman is the United States is 65 inches tall and the standard deviation is 3 inches.  If Zsike is 67 inches tall, what is her z-score?

One year Terry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 3.02. Also, Karen had the lowest ERA of any female pitcher at the school with an ERA of 3.24. For the males, the mean ERA was 4.364 and the standard deviation was 0.639. For the females, the mean ERA was 3.801 and the standard deviation was 0.959 Find their respective z-scores. Which player had the better year relative to their peers, Terry or Karen? (Note: In general, the lower the ERA, the better the pitcher.) Terry had an ERA with a z-score of Karen had an ERA with a z-score of (Round to two decimal places as needed) Which player had a better year in comparison with their peers? OA. Terry had a better year because of a higher z-score. OB. Karen had a better year because of a lower z-score. OC. Terry had a better year because of a lower z-score. O D. Karen had a better year because of a higher z-score. GIL

The average McDonald's restaurant generates $2.4 million in sales each year with a standard deviation of 0.7. Carissa wants to know if the average sales generated by McDonald's restaurants in New Mexico is different than the worldwide average. She surveys 18 restaurants in New Mexico and finds the following data (in millions of dollars): 2.1, 2, 2.9, 1.7, 1.8, 2.3, 2.1, 2.1, 3.3, 1.4, 1.6, 1.4, 1.4, 2.3, 2.6, 2.7, 2.7, 1.7 Perform a hypothesis test using a 8% level of significance. Step 1: State the null and alternative hypotheses. Ho: pv 2.4 Ha: Ev 2.4 (So we will be performing a two-tailed test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are normally distributed v with and distribution standard deviation distribution mean Step 3: Find the p-value of the point estimate. P(zv [ p-value = Step 4: Make a Conclusion About the…

According to the Bureau of Labor Statistics, the mean salary for registered nurses in Kentucky was $56,279. The distribution of salaries is assumed to be normally distributed with a standard deviation of $5,902. Someone would like to determine if registered nurses in Ohio have a greater average pay. To investigate this claim, a sample of 168 registered nurses is selected from the Ohio Board of Nursing, and each is asked their annual salary. The mean salary for this sample of 168 nurses is found to be $56,485.465.  Describe the sampling distribution of the sample mean salary when samples of size 168 are selected. Mean (μ y-bar): _____ Standard Deviation (σ y-bar): _____ Shape: The distribution of y-bar is __________ (normally distributed/not normally distributed) because __________ (the population of salaries is NOT normally distributed/the sample size is large/the sample size is NOT large/the population of salaries is normally distributed) What conjecture has been made? The mean…