For a ground state Cd atom (Z = 48), how many electrons in total have an angular quantum number ℓ = 0 ?

What is the greatest magnitude of the orbital angular momentum L for an electron in a state with principal quantum number n = 5? Group of answer choices 4.90 4.47 5.48 3.46

Consider the atom having the electron configuration 1s2 2s2 2p6 3s2. Assume that the z components of both the orbital abd spin angular momenta of the electron in the 3p subshell are positive. What are the quantum numbers that describe the state of this electron. n=3 l=1 m=-1 s=1/2n=3 l=1 m=2 s=1/2n=3 l=2 m=1 s=1/2n=3 l=1 m=1 s=1/2n=3 l=2 m=2 s=-1/2 Can we say which one is correct?

An electron occupying the n = 6 shell of an atom carries z-component orbital angular momentum = (–2) × h/2π. Given that the electron’s total orbital angular momentum is x × h/2π, what is the minimum possible value of number x(remember to use the scientific notation)?

The wave function for hydrogen in the 1s state may be expressed as Psi(r) = Ae−r/a0, where A = 1/sqrt(pi*a03) Determine the probability for locating the electron between r = 0 and r = a0.

In a particular state of the hydrogen atom, the angle between the angular momentum vector L →and the z-axis is u = 26.6°. If this is the smallest angle for this particular value of the orbital quantum number l, what is l?