For a bolted assembly, the stiffness of each bolt is ka = 700 MN/m and the stiffness of themembers is km = 2100 MN/m per bolt. The joint is subject to occasional disassembly formaintenance and should be preloaded accordingly. An external load is applied to the entirejoint with P = 360 kN. Assume the load is equally distributed to all the bolts. It has beendetermined to use M12x1.75 grade 8.8 bolts with rolled threads.(a) Determine the minimum number of bolts necessary to avoid yielding of the bolts.(b) Determine the minimum number of bolts necessary to avoid joint separation.

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Answered: For a bolted assembly, the stiffness of…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Two gas struts with a extended length of 26", compressed length of 16" and a stroke of 10" with a .39" rod and .866" body is being used to hold a door weighing 40 lbs. prior to use, the owner would like to ensure the ball bearings can hold the load of the gas struts closed. The gas strut is a 20 lb compression gas strut, how much force does it take to keep gas strut closed if you were to push straight down in order to compress. Note: The answer is not 20lbs and I need all equations.
A 30-mm thick AISI 1020 steel plate is sandwiched between two 10-mm thick 2024-T3 aluminum plates and compressed with a bolt and nut with no washers. The bolt is M10 x 1.5. property class 5.8. (a) Determine a suitable length for the bolt, rounded up to the nearest 5 mm. (b) Determine the bolt stiffness. (c) Determine the stiffness of the members.
only HANDWRITTEN answer needed ( NOT TYPED)
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Design of a bolted assembly using a single M16x2 class 8.8 coarse-thread bolt has resulted in a joint where bolt stiffness is k, = 6 N/mm and the overall member stiffness - 18 N/mm. The fastener is to be reused (nonpermanent). Question 1 Value of joint stiffness constant: 0.25 4.0 0.5 0.1 Question 2 Magnitude of bolt tightening load (preload) Fi [kv]: 85 71 94 63
Pravinbhai
Give me correct answers please
The relation between joint and frame is J = (2N - 3) (Where N - number of members, J - Number of Joints ) Sentence is : Select one: True False
A thin-walled spherical vessel, which is made of AISI C1020, as rolled steel has a diameter of 2.5 ft. The joint efficiency of the vessel is 80%. Internal pressure of the gas inside the vessel varies continuously from 200 psi to 400 psi. If for a Factor of Safety of 1.75 based on Soderberg criterion and the surface of the vessel is polished, find the minimum safe thickness of the vessel.
19. The Knuckle Joint is made from SAE 1020 Steel having an allowable tensile strength of 15,000 psi and an allowable shear strength of 7500 psi. The axial load is 1 ton (recall, 1 ton = 2205 lb). Yoke Pin Rod -A The dimensions are as follows: D-0.652 in d-0.652 in c = 0.66 in b = 0.33 in m = 1.306 in e = 0.505 in Determine: a) Tensile stress (psi) at section A-A b) Factor of safety for a) c) Shearing stress (psi) in the pin d) Factor of safety for b) e) Bearing stress (psi) between the pin and the rod f) Factor of safety for e) g) Bearing stress (psi) between the pin and the yoke h) Factor of safety for g) i) Tensile stress (psi) across the hole in the rod j) Factor of safety for i) k) Tensile stress (psi) across the hole in the yoke 1) Factor of safety for k)
Te - Effective throat thickness well in mm = 6 sin45° Consider the following drawing in which plate 1 is welded onto plate 2 as shown for tensile and shear loading. The plates are fillet welded with a weld thickness of 6 mm as shown for a length of 150 mm. The plates have an ultimate strength of 275 MPa and the welding was done with F70 welding electrodes, which possesses an ultimate strength of 483 MPa. Consider a partial factor of safety of 1.7 for the welded joint and determine the design strength of the weld joint, both in tension (Tdw) and in shear (Vdw) due to the forces acting on it. a) Determine the design strength of the following weld in tension ( ) due to vertical forces. b) Determine the design strength of the weld in shear ( ) due to horizontal forces. Attached pic is shear equation for calculation Tension equation for calculation is: Tdw = FyLwte /Ymw
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