Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- Assume that attached earlobes are an autosomal recessive trait with 73% penetrance. If one parent is heterozygous (Aa) and the other homozygous recessive (aa) for the attached earlobe gene, what is the probability that their second child will have attached earlobes? O 73% O 36.5% O 50% O 63.5% O 27% O 13.5% O 18.75%arrow_forwardA colorblind man marries a female who is a carrier for colorblindness. What is the probability that they will have a child who is colorblind?arrow_forwardA human female who is heterozygous for the recessive, sex-linked trait causing red-green color blindness, marries a normal male. What proportion of their male progeny will have red-green color blindness?arrow_forward
- A couple can both see red (a sex-linked trait). The allele responsible for red color-blindness is recessive on the X-chromosome. The woman is a carrier for this condition. What are the likely genotypes of this couple? What is the probability of the couple having a daughter who is red colorblindarrow_forwardFor each of the following genotypes state whether you have a homozygous or heterozygous for each trait (you may need to use 2 terms for one genotype). AaGG Rrgg TTGgarrow_forwardIn a dihybrid cross (2 sets of alleles, independently assorted) each parent (heterozygous for both traits) can have 4 combinations of alleles in their gametes), so to calculate the odds for inheritance of particular genetic combinations, we must draw out 16 squares. In the case of our purple/yellow and starchy/sweet corn kernels, we can calculate the odds of the possible phenotypes. Purple & starchy: purple & sweet: yellow & starchy: yellow & sweet, can be calculated as O 9:2:2:3 9:3;3;1 O 5:4:4:3arrow_forward
- In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non‑freckled, normal visioned girl or a non-freckled, normal visioned boy? What is the probability that the first four children born to the couple will be freckled and normal visioned girls?arrow_forwardMendel’s observation that two different traits could be inherited independently of each other can be explained by understanding that: During meiosis, the process of chromosome assortment into daughter cells is random Alleles of the genes reside on homologous chromosomes All of the listed choices are correct During meiosis, maternal and paternal members of homologous chromosomes are distributed separately into daughter cellsarrow_forward
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