Following are the results of a shrinkage limit test: Initial volume of soil in a saturated state = 24.6 cm³ Final volume of a soil in a dry state = 15.9 cm³ Initial mass in saturated state = 44g Final mass in dry state = 30.1g G, = 2.7

Following are the results of a shrinkage limit test: Initial volume of soil in a saturated state = 24.6 cm³ Final volume of a soil in a dry state = 15.9 cm³ Initial mass in saturated state = 44g Final mass in dry state = 30.1g G, = 2.7

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Minimum principal stress

A: To find minor / minimum principal stress

Q: When a bar of certain material 40 mm square is subjected to an axial pull of 1,60,000 N the…

A: From question,Axial load ,P=160000 NCross section area,

Q: Problem # 5: For the composite area shown, calculate the location of centroid with respect to…

Q: What can you conclude?

Q: A uniform concrete slab of total weight W is to be attached, as shown, to two rods whose lower ends…

A: Given:- The weight of the uniform concrete slab = W The lower ends of the two rods are on the same…

Q: #Q3. W/C 0.45 0.5 0.55 fc (MPa) 21 24 23 Then, 1. Fit a polynomial and find fc @ W/C=0.52 2. Find…

Q: Problem A sample of a dry coarse grained material of 500 grams was shaken through a nest of sieves…

A: Size of sieve for which 60% of sand passes, D60=2mmSize of sieve for which 300% of sand passes,…

Q: Give the value of Plastic modulus for ISHB 250 @ 54.7 kg/m weight.

A: Brief concept introduction- ISHB 250 is the short name for the Indian Standard Heavy Weight Section…

Q: Strength of Materials

Q: 30kg and ma= 70 kg. Between all of the contacting swrfaces, u, = 0.1. What is the largest force F…

Q: In geometric tolerance, MMC means. material condition Select one: O a. moderate O b. maximum O .…

A: Given They ask for fullform of MMC

Q: Stress analysis Task Question / Calculate the critical design loads applied to the Stirling Engine…

A: Please find the answer in the below attachments

Q: P 2P A В C L 2 Figure A d b Figure B

A: (a) Determine the maximum horizontal shear stress in the beam. (b) If the allowable shear stress…

Q: A rigid foundation is subjected to a vertical column load, P = 355 kN, as shown in Figure 11.43.…

A: Soil is one of the important aspects of construction material. So one needs to find out its…

Q: A beam, which is rectangular, has a base of 250 mm, and d = 575 mm. The beam is singly reinforced,…

A: Using limit state method Strain in concrete 0.003 Strain in steel 0.005 Depth 575 mm Width 250mm…

Q: A tensile force of 20 kN is applied to a specimen with a gage length of 50mm. It is then noted that…

A: Given data, Tensile force = 20 kN Gauge length = 50 mm After force gauge length = 50.122 mm…

Q: 2. The masses of the blocks are ma = 30 kg and mg = 70 kg. Between all of the contacting surfaces,…

Q: Softwood rays are typically 5 1 10 8 ◆ cells wide.

Q: Determine the Poisson's ratio and bulk modulus of a material, for which Young's modulus is 1.2 x 10…

A: Given data, Young's modulus E = 1.2×105 N/mm2 Modulus of rigidity G = 4.5×104 N/mm2

Q: 3. Determine the normal force between the crate and the surface 4. Determine the force P needed to…

A: Given- W = 856 N Frictional coefficient - μs = 0.3 height of block = h = 2 m Width of block = b = 1…

Q: What will be the relation between E and K Where, E= Young's modulus and K= bulk modulus when…

A: Given. What will be the relation between E and KPoisson's ratio=0.30

Q: B. A volume of one cum of water is subjected to a pressure increase of 14MP.. 1. Compute the change…

A: 1) negative sign represent the decrease in volume

Q: Tension specimens (diameter d0 0.500 in., gage length L0 2.00 in.) made of structural materials A…

A: Given, Do = 0.5 in Lo = 2 in

Q: 3. A solia cement rectangular ienti (beam) with length L = 1.5 m 1s positioned as shown. The lenti…

A: Boundary Conditions :For fixed end,y(0) = 0y'(0) = 0For Simply supported end,y(L) = 0y''(L) = 0

Q: The void ratio can never be a) Less than 1 b) Greater than 1 c) Less than zero d) Equal to 1

A: Answer : Option (c) less than zero is correct Explanation is given in next step.

Q: A rectangular block is 129 mm long in the X direction, 100 mm wide in the Y direction, and 56 mm…

Q: Assuming elastic modulus as 190 GPa and shear modulus as 100 GPa for a [0.001 0.003 material, a…

A: Prob 3: Step 1: E=190 GPa G=100 GPa

Q: When a pressure of 650 psi is applied to a solid, its specific weight increases from 310 lb>ft3 to…

A: given- pressure P=650 psispecific weight increases from 310 lb/ft3 to 312lb/ft3

Q: What will be the relation between E and K Where, E= Young's modulus and K= bulk modulus when…

A: Given. Find the ratio between E and K ?Where, Poisson's ratio,μ= 0.25

Q: The rectangular piece of wood, 76 mm by 174 mm, is used as a compression block. The grain of the…

A: Determination of shearing stress on the plane of grain

Q: 2. Fill In the blanks. A soll that is weathered in place is called a soil. A soil that is weathered…

Q: Discuss the results in the following graph?

A: To

Q: IV. CALCULATION 1. Buoyancy We = BF - Ww BF = y x V, Where: W. - weight of the specimen w. = weight…

Concept explainers

Weight-Volume relationships

Weight is defined as the quantity of matter contained in a body. Weight can also be defined as the force acting on a body due to gravity. Mathematically, weight can be defined as-

Question

Determine the shrinkage limit and saturated unit weight if e = 0.467

Following are the results of a shrinkage limit test:
Initial volume of soil in a saturated state = 24.6 cm³
Final volume of a soil in a dry state = 15.9 cm³
Initial mass in saturated state = 44g
Final mass in dry state = 30.1g
G, = 2.7

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given data

VIEW

Step 2: Calculate the shrinkage limit and saturated unit weight

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

2.3.5 PROBLEMS Problem 2.3-1 Data for yield stresses of reinforcing bars in MPa have been presented in terms of frequency distribution below. Represent these data graphically in terms of histograms, frequency polygon, and ogives. Table 2.3-12: Frequency table for yield stresses of reinforcing bars in MPa. Classes Frequency 350 365 365 380 380 395 395 410 9. 410 425 8 425 440 8 440 455 9. 455 470 1 470 485 1
which is bigger, porosity or void ratio?
2) A given material the linear limit is 1.8 * 106 N/ m? and the ultimate compressive strength is 1.8 *10 N/m² and cross sectional area is 6 *104, If the length change by 20%, What is Y material ? A) 9*105 N / m? B) 9*10 6 C) 6 * 10° N / m ? D) 9 *106 N / m?
Provide your reasons why the shape of the shear strength function is not similar to that of permeability function.
Determine the uniformity coefficient and coefficient of gradation from the following data:
A) compare by drawing between the Clay minerals of 1/1 and clay minerals of 1/2
the composite area shown in the figure below is composed of two rectangles. use b = 4.97m., h = 3.73 m. and t =1.48m. determine the radius of gyration about the indicated x-axis.
When a bar of certain material 40mm square is subjected to an axial pull of 1,60,000N the extension on a gauge length of 200mm is 0.1mm and the decrease in each side of the square is 0.005mm. Calculate Young's modulus, Poisson's ratio. Shear modulus and bulk modulus for this material.
Define Total Stress Analyses