Fluctuating in a Circle A A one kg bead is restricted to a two meter radius vertical circle. When the bead rolls along the circular track, there is no resistance. At the top of the circle, at point "A," the bead travels at a speed of 10 m/s, and its total mechanical energy is assumed to remain constant as it travels around the circle. From A to B in a counterclockwise direction should take the bead around 0.62 seconds. 10 m/s 2 m 1 Important: when expressing vector directions, use the "conventional" angle notation of 0 degrees 0 minutes and 30 seconds. Find the mean speed (in meters per second) traveling from point "A" to point "B." (based on the 0.62 seconds mentioned in the description).
Fluctuating in a Circle A A one kg bead is restricted to a two meter radius vertical circle. When the bead rolls along the circular track, there is no resistance. At the top of the circle, at point "A," the bead travels at a speed of 10 m/s, and its total mechanical energy is assumed to remain constant as it travels around the circle. From A to B in a counterclockwise direction should take the bead around 0.62 seconds. 10 m/s 2 m 1 Important: when expressing vector directions, use the "conventional" angle notation of 0 degrees 0 minutes and 30 seconds. Find the mean speed (in meters per second) traveling from point "A" to point "B." (based on the 0.62 seconds mentioned in the description).
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Fluctuating in a Circle A A one kg bead is restricted to a two meter radius vertical circle. When the bead rolls along the circular track, there is no resistance. At the top of the circle, at point "A," the bead travels at a speed of 10 m/s, and its total mechanical energy is assumed to remain constant as it travels around the circle. From A to B in a counterclockwise direction should take the bead around 0.62 seconds. 10 m/s 2 m 1 Important: when expressing vector directions, use the "conventional" angle notation of 0 degrees 0 minutes and 30 seconds. Find the mean speed (in meters per second) traveling from point "A" to point "B." (based on the 0.62 seconds mentioned in the description).
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