Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Find the voltage across the capacitor as a function of time for t>0 for the circuit in Fig.
8.72. Assume steady-state conditions exist at t=0
1a 025 H
20 v
Figure 8.72
For Prob. 8. 18.
Chapter 8, Solution 18.
When the switch is off, we have a source-free parallel RLC circuit.
0.5
VLC
2,
J0.25x1
2RC
a<@,
underdamped case o, - Va
4-0.25 =1.936
L(0) = i(0) = initial inductor current = 20/5 - 4A
V0) = v(0) = initial capacitor voltage =0 Vv
v(1) =e(4, cosot+ A, sin @,t)=e®*" (A, cos 1.936 + A, sin1.9361)
v(0) -0 - A,
dv
"(-0.5)(4, cos 1.936t + A, sin 1.936) + e0s (-1.9364, sin 1.936t +1.9364, cos1.9361)
dt
dv(0)
di
Thus,
(V_ + RI
RC
(0+4)
--0.54, +1.9364,
A--2.066
-(v.+IR)
%3D
41) =-2.066e
sin 1.936t
R
R
0.50
How did he get the value
inside the red circle
88
ט
expand button
Transcribed Image Text:Find the voltage across the capacitor as a function of time for t>0 for the circuit in Fig. 8.72. Assume steady-state conditions exist at t=0 1a 025 H 20 v Figure 8.72 For Prob. 8. 18. Chapter 8, Solution 18. When the switch is off, we have a source-free parallel RLC circuit. 0.5 VLC 2, J0.25x1 2RC a<@, underdamped case o, - Va 4-0.25 =1.936 L(0) = i(0) = initial inductor current = 20/5 - 4A V0) = v(0) = initial capacitor voltage =0 Vv v(1) =e(4, cosot+ A, sin @,t)=e®*" (A, cos 1.936 + A, sin1.9361) v(0) -0 - A, dv "(-0.5)(4, cos 1.936t + A, sin 1.936) + e0s (-1.9364, sin 1.936t +1.9364, cos1.9361) dt dv(0) di Thus, (V_ + RI RC (0+4) --0.54, +1.9364, A--2.066 -(v.+IR) %3D 41) =-2.066e sin 1.936t R R 0.50 How did he get the value inside the red circle 88 ט
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