Find the specific heat of an unknown bodily fluid if the temperature of a 50 g sample increases by 3oC when 75 cal of heat is added.

When 17.98 g of calcium chloride (CaCl2) is dissolved in 681.87 g of water in a coffee-cup calorimeter at 26.4°C, the temperature increased to 28.4 °C. Assuming that the specific heat of the mixture is the same as the specific heat of pure water (4.184 J/g-°C), calculate the AH (in kJ/mol CaCl2) in the dissolution process. MW of CaCl2 = 110.9g/mol CaCl2 (s) →→ Ca+2 (aq) + 2 CI¯ (aq) Show your complete solution. Express your answer in two decimal places.

When 130. mL of 0.198 M NaCl(aq) and 130. mL of 0.198 M AgNO3(aq), both at 21.8°C, are mixed in a coffee cup calorimeter, the temperature of the mixture increases to 24.2°C as solid AgCl forms. NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq) This precipitation reaction produces 2.60 ✕ 103 J of heat, assuming no heat is absorbed by the calorimeter, no heat is exchanged between the calorimeter and its surroundings, and that the specific heat and density of the solutions are the same as those for water (4.18 J/g·°C, and 0.997 g/mL, respectively). Using this data, calculate ΔH in kJ/mol of AgNO3(aq) for the given reaction. This is the complete question, nothing was left out. Thank you

When 6.54 grams of Zn is placed in 500.0 mL of 1.00 M CuSO4(aq) in a coffee cup calorimeter, it reacts completely to displace copper. The temperature of the solution rises from 20.0˚C to 30.4˚C. Assume the coffee cup itself gains no heat and that the solution has the same density (1.00 g/mL) and specific heat (4.184 J/g˚C) as pure water. (a) How much heat does the solution gain during this reaction? (in J)