Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- P1) For the unit-sized inverter shown in figure Error! Reference source not found., find analytically the approximate rise and fall times (10% to 90%) assuming the inverter derives a 0.3pF load capacitor. 2.5V V₁ W = 6 L P L = 0.25μm 0.3pF (HH). = 2 n Figure 1: CMOS Inverterarrow_forwardQ2 Draw the schematic circuit for a CMOS inverter and the relative voltage transfer characteristic showing the different regions of operation. (a) The output of the CMOS inverter is connected to a capacitance of 5 pF, to the ground, representing the gate of NMOS at the input of a logic circuit. Calculate the total power dissipation in the inverter if there is a square wave input signal switching at 40 MHz with an amplitude of VpD consider VoH= VDD and VOL=0 and a quiescent current lo = 10 µA. (b) = 5 V. For the calculation The obtained total power dissipation is too high for a specific application. Design a circuit, by adding a single external component, to reduce the total power dissipation by 20 %. Justify your choice and state any assumption. (c)arrow_forward2/ Consider a CMOS inverter biased at VDD = 8v with transistor parameters of KN=Kp and VTN = - VTp =Iv Determine the critical voltages on the voltage transfer curve of a CMOS inverter.arrow_forward
- 2. Which of the following statements on NMOS, PMOS and CMOS is NOT correct? A. When voltage between gate and source is greater than threshold, the connection betweer drain and source is closed for NMOS. B. When voltage between gate and source is greater than threshold, the connection betweer drain and source is closed for PMOS. C. A CMOS can be composed of an NMOS and a PMOS. D. When the input for a CMOS is low, the output of it is high.arrow_forwardA full bridge inverter with RLC load having the following values: R=7.5 Ohms, L=12.5 mH, C=22 uF. The switching frequency is 500 Hz and the DC input voltage is 180V. The THD of the load current is equal to (consider up to the fifth harmonics): Select one: Oa. 8% O b. 12% O c. 6% d. 4%arrow_forwardJ VDD RD - Vout You may have already noticed that the common source amplifier circuit is basically the same as the NMOS RTL inverter, just used for different purposes. The slope of the inverter VTC (Vout-Vin curve) is also the small- signal voltage gain of the common source amplifier. Assume VDD = 5V and Vin M₁ Vthn 0.7 V for the NMOS, use PSPICE to simulate the VTC (sweep from 0 to 5 V) of the common source amplifier for the following conditions: (a) Fix RD = 100 kN, L = 1 µm, W = 1 μm. Vary kn² = 20, 100, and 500 μА/V². (b) Fix kn' = 100 µA/V², R₁ = 100 kQ, L = 1 μm. Vary W = 1, 5, and 50 μm. (c) Fix kn' = 1 100 μA/V², L = 1 µm, W= 1 µm. Vary RD = 10 k2, 100 kQ, 1 MQ. Compare the slopes of the VTCs (which correspond to the voltage gains of the amplifiers) you obtained from the various conditions in a-c and explain your results.arrow_forward
- ..A CMOS Inverter using a Power Supply of 3.3 V and Channel length = 20 nm is built in a process with the following specification: NFET: Process Transconductance = 167 (µA/V²); Threshold voltage = 0.58 V Width= 6 µm PFET: Process Transconductance = 75 (µA/V²) ; Threshold voltage = - 0.63V ; Width = 11 µm %3D a) Calculate Device Transconductances of the nFET and the pFET. b) Estimate the Midpoint voltage of the Inverter.arrow_forwardSketch a 3-input NOR gate with transistor widths chosen to achieve effective rise and fall resistance equal to that of a unit inverter (R). Annotate the gate with its gate and diffusion capacitance's. Assume all diffusion nodes are contacted. Then sketch equivalent circuits for the worst case falling output transition and for the rising output transition.arrow_forward
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