MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- The amount of time a service technician needs to change the oil in a car is uniformly distributed between 11 and 21 minutes. Let X = the time needed to change the oil on a car. c. Find the 50th percentile. Round to the nearest minute.arrow_forwardSolve the problem.The diameter of ball bearings produced in a manufacturing process can be explained using a uniform distribution over the interval 6.5 to 8.5 millimeters. What is the mean diameter produced in this manufacturing process? Select one: A. 8.0 millimeters B. 7.5 millimeters C. 8.5 millimeters D. 7.0 millimetersarrow_forwardProvide an appropriate response. Use the Standard Normal Table to find the probability. IQ test scores are normally distributed with a mean of 105 and a standard deviation of 11. An individual's IQ score is found to be 114. Find the z-score corresponding to this value. Round the answer to the nearest hundredth. O A. -0.82 OB. -1.22 O C. 0.82 O D. 1.22 Carrow_forward
- Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 1.50 and 2.25 Click to view page 1 of the table. Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. O A. OB. Oc. z=1.50 z=2.25 z=1.50 z=2.25 z=1.50 z=2.25 The probability of getting a reading between 1.50°C and 2.25°C isO. (Round to four decimal places as needed.)arrow_forwardAssume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is between -2.05 and 3.87 and draw a sketch of the region. Sketch the region. Choose the correct graph below. OA. OB. OC. OD. -2.05 3.87 2.05 3.87 -2.05 3.87 -2.05 3.87 The probability is (Round to four decimal places as needed.)arrow_forwardNeed helparrow_forward
- Cumulative frequency Male Beagles 50- 45- 40- 35- 30- 25- 20- 15- 10- 5- 0- 19.5 22.5 25.5 28.5 31.5 34.5 Weight (in pounds) 55-arrow_forwardUse the standard normal table to find the z-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. P 25 Click to view page 1 of the table. Click to view page 2 of the table. The z-score that corresponds to P25 is (Round to two decimal places as needed.)arrow_forwardAssume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the casebelow, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 0.25 and 1.25 Click to view page 1 of the table. LOADING... Click to view page 2 of the table. LOADING... Draw a sketch. Choose the correct graph below. A. z=0.25z=1.25 A graph with a bell-shaped curve, divided into 3 regions by 2 lines from top to bottom, both on the right side. The region between the 2 lines is shaded. Moving from left to right, the z-axis below the first line is labeled "z=0.25". The z-axis below the second line is labeled "z=1.25". B. z=0.25z=1.25 A graph with a bell-shaped curve, divided into 3 regions by 2 lines from top to bottom, both on the right side. Moving from left to right,…arrow_forward
- Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 1.50 and 2.25 Click to view page 1 of the table. Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. O A. The probability of getting a reading between 1.50°C and 2.25°C is (Round to four decimal places as needed.) d Normal Table (Page 2) .00 Standard Normal (z) Distribution: Cumulative Area from the LEFT .5000 5398 5793 .6179 .6554 .6915 7257 .7580 7881 .8159 .8413 8643 .8849 .9032 9192 9332 9452 .9554 .9641 9713 9772 .9821 9861 0007 .01 5040 5438 5832 6217 .6591 z=1.50 z=2.25 6950 7291 .7611 7910 .8186 .8438 8665 8869 9049 9207 9345 9463 .9564 9649 .9719 9778 9826 9864 .02 5080 5478 5871 6255 6628 .6985 7324 7642 7939 .8212 8461 8686 8888 .9066 9222 9357 9474 .9573 9656…arrow_forwardAssume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)arrow_forwardConsider a sample data set with the summary statistics s= 112, Q = 58, and Q, =203. %3D a. Calculate IQR. b. Calculate IQR/s. c. Is the value of IQR/s approximately equal to 1.3? What does this imply? a. IQR =arrow_forward
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