Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject H, for the given level of significance a. Right-tailed test with test statistic z = 1.00 and a = 0.04 ..... P-value = (Round to four decimal places as needed.)
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- Construct a confidence interval for the ratio of the population variances given the following sample statistics. Round your answers to four decimal places. n1=9, n2=18, s1^2/s2^2=1.17, a=0.1do fast ..with explanation both require..You wish to test the following claim (Ha) at a significance level of a = 0.001. H,:P = P2 Ha:pi > p You obtain 303 successes in a sample of size n = 488 from the first population. You obtain 159 successes in a sample of size ry = 266 from the second population. What is the test statistic for this sample? test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion. O There is not sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion. O The sample data support the claim that the first population…
- Find the P-value for the indicated hypothesis test with the given standardized test statistics z. Decide whether to reject H0 for the given level of significance α. Left-tailed test, z=-1.32, α=0.10 Right-tailed test, z=2.46, α=0.01 Two-tailed test, z=-1.68, α=0.05You wish to test the following claim (Ha) at a significance level of a = 0.002. = Ho: P₁ Ha: P1 P2 P2 You obtain a sample from the first population with 594 successes and 78 failures. You obtain a sample from the second population with 558 successes and 44 failures. The test statistic is... O in the critical region not in the critical region critical value = test statistic = This test statistic leads to a decision to... reject the null hypothesis fail to reject the null hypothesis [three decimal accuracy] [three decimal accuracy] As such, the final conclusion is that... O There is sufficient evidence to support that the first population proportion is less than the second population proportion. There is not sufficient evidence to support that the first population proportion is less than the second population proportion.Help with Q2
- We have provided a sample mean, sample standard deviation, and sample size. In each case, use the one-mean t-test to perform the required hypothesis test at the 5% significance level. x = 21, s = 4, n = 32, H0: μ = 22, Ha: μ<22HW Help, Thank You!!!K The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 5.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Click the icon to view the display from technology. D iew an example Get more help. 42 W S Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? OA. Ho: 5.00 Mbps J D. Ho: -5.00 Mbps H₁: - Clear all : - ; X option F11 { [ ? + = 1 I Check answer F12 } ] delete retu
- Please help me with this question.find p value for left tailed test. test statistic t = -2.484 sample size n = 22Consider the hypothesis test below. Ho : P1 – P2 0 The following results are for independent samples taken from the two populations. Sample 1 Sample 2 100 n2 = 300 P1 = 0.27 P2 = 0.15 Use pooled estimator of p. a. What is the p-value (to 4 decimals)? Use Table 1 from Appendix B. b. With a = 0.05, what is your hypothesis testing conclusion? Select your answer -