Find the force of electrical attraction between a proton and an electron that are 8.7 x 10-11m apart.Compare this to the gravitational force between these particles.NNeed Help?Read ItTalk to a TutorO vA 11:44escDII%23$&backspace123468tabetyafentershiftVnmshiftaltaltstr)

Given : Charge of electron, qe = - 1.6 x 10-19 C Charge of electron, qp = 1.6 x 10-19 C…

Answered: Find the force of electrical attraction…

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Find the force of electrical attraction between a proton and an electron that are 8.7 x 101 m apart.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 5P

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Nobel laureate Richard Feynman (19181088) once said that if two persons stood at arms length from each other and each person had 1% more electrons than protons, the force of repulsion between them would be enough to lift a weight equal to that of the entire Earth. Carry out an order-of-magnitude calculation to substantiate this assertion.
Use the following constants if necessary. Coulomb constant, k=8.987×109N⋅m2/C2. Vacuum permitivity, ϵ0=8.854×10−12F/m. Magnitude of the Charge of one electron, e=−1.60217662×10^-19C. Mass of one electron, me=9.10938356×10−31kg. The gravitational acceleration near the surface of Earth g=9.8m/s2. Unless specified otherwise, each symbol carries their usual meaning. For example, μC means microcoulomb . step 1: Two small identically charged conducting spheres 1 and 2 of equal mass are hung from a fixed support with non conducting threads of equal length as shown in the figure. Both the spheres have equal mass m1=m2=m and equal charge q1=q2=q. Assume that the charge of each sphere is q=36nC , the length of the thread is L=233cm and the horizontal separation is x=17cm. You must draw the figure properly in your pdf. The x and y directions are shown in the figure. You have the liberty to choose any point as the origin of your coordinate system. (Hint: You may find it convenient to choose q1 or…
Use the following constants if necessary. Coulomb constant, &= 8.987 x 10°N. m/ce 0- 8.854 x 10-12/m me= 9.10938356 x 10-3g means micro coulomb Vacuum permitivity, . Magnitude of the Charge of one electron, e=-1.60217662 x 10-1 . Mass of one electron, Unless specified otherwise, each symbol carries their usual meaning. For example, pC Consider two charges gl = 37e and 2= 18 e at positions (20, 38, 37) and ( 40) respectively where all the coordinates are measured in the scale of 10-m or nano meters. If position vector of the charge g1 is 1 and charge a is a) Find the relative position vector that points from charge g to charge . - component Give your answer to at least three significance digits. y component Give your answer to at least three significance digits. m. I component Give your answer to at least three significance digits. m. b) Calculate the force actir a due to 2. I component of the force Give your answer to at least three significance digits. y component of the force Give…
Please Answer all the Questions Use the following constants if necessary. Coulomb constant, k=8.987×109N⋅m2/C2 . Vacuum permitivity, ϵ0=8.854×10−12F/m . Magnitude of the Charge of one electron, e=−1.60217662×10−19C . Mass of one electron, me=9.10938356×10−31kg . Unless specified otherwise, each symbol carries their usual meaning. For example, μC means microcoulomb . Consider two charges q1=−48e and q2=13e at positions (34,-33,27) and (39/√3,-48/√2,−28) respectively where all the coordinates are measured in the scale of 10−9m or nano meters. If position vector of the charge q1 is r1 and charge q2 is r2. a) Find the relative position vector that points from charge q1 to charge q2 . x component y component z component b) Calculate the force acting on q1 due to q2 . x component of the force y component of the force z component of the force Now consider another charge q3=−40e is in the xyz system positioned at (11/√3,29√2,25) . Calculate the net force acting on q1 and q2 . c) Net Force on…
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Use the following constants if necessary. Coulomb constant, k = 8.987 x 10° N - m/c. Vacuum permitivity, 60 = 8.854 x 10-12 F/m. Magnitude of the Charge of one electron, e = -1.60217662 x 10-19 C. Mass of one electron, m. = 9.10938356 x 10-31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, uC means micro coulomb. Suppose you have g = 17 µC charge placed at the orign of your coordinate system. a) Using Gauss's law, find the electric field at distance ri = 9 m from the charge. b) Now you place a hollow conducting sphere of inner radius a = 4.5 m and outer radius b = 18.0m. Calculate the net enclosed charge by the Gaussian surface of radius r1. b.
The gravitational force between two electrons is weaker than the electric force by the order of 10-40. Yet the gravitational interactions of matter were observed and analyzed long before electrical interactions were understood. Why?
How many excess electrons can be counted in a rubber rod of - 3 *0.00001 nano Coulombs of charges? Your Answer: Answer P Type here to search a O 41F Haze ^6 O R AM 2/11/2022 257AM 4 d0 12 te to 米 "g. esc delete home end Da up %23 %24 & 6 num 3 8. 9 %3D + backspace lcok T. Y P 7. 8. tab home Dg up H J K 6. enter caps lock prt sc M * shift 2 3. shift T end De dn alt cul fn alt ins
Use the following constants if necessary. Coulomb constant, k = 8.987 × 10º N · m² /C². Vacuum permitivity, €o = 8.854 × 10-12 F/m. Magnitude of the Charge of one electron, e = -1.60217662 × 10¬19 C. Mass of one electron, mẹ = 9.10938356 × 10 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, uC means micro coulomb . -31 P R
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Use the following constants if necessary. Coulomb constant, k = 8.987 x 10° N m2 /C. Vacuum permitivity, eo = 8.854 x 10 12 F/m. Magnitude of the Charge of one electron, e =-1.60217662 x 10-19 C. Mass of one electron, m, = 9.10938356 x 10-31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, uC means micro coulomb. Y R. Suppose you have 5 point charges q to q, distributed along a semi-circle maintaining equal distance. The charge q6 is on the center of the circle which is also the origin of given coordinate system. The radius of the semi-circle is R = 34 cm and the magnitude of the charges are as follows : 91 = = 19 µC, q2 = q4 = 32 µC and q = q6 = -25 µC. a) Find the vector that points from q to g6 and call it F1,6- b) Calculate the coulomb force on g6 due to q in unit vector notation and call it F16 c) Find the vector that points from q3 to g6 and call it F3,6- d) Calculate the coulomb force on q6 due to g in unit vector notation and call it F36. e)…