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Find the energy of the photon released in the transition from n₁ = 6 to n₂ = 1 for a hydrogen atom. (Note: Use Rydberg Formula)

Find the energy of the photon released in the transition from n₁ = 6 to n₂ = 1 for a hydrogen atom. (Note: Use Rydberg Formula)

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Find the energy of the photon released in the transition from n₁ = 6 to n₂ = 1 for a hydrogen atom. (Note: Use Rydberg Formula)
Transcribed Image Text:Find the energy of the photon released in the transition from n₁ = 6 to n₂ = 1 for a hydrogen atom. (Note: Use Rydberg Formula)
Expert Solution
Concept and Principle:
  • When an electron moves from a higher state to a lower state it will release energy in the form of electromagnetic radiation. The wavelength of the released photon is given by the Rydberg formula.

 

  • Rydberg formula is given by,

λ=1R∞(n12n22n12−n22)

Here R∞ is the Rydberg constant and has a value of 1.097373 × 107 m-1, and n1 and n2 are the states in which transition takes place.

 

  • Combining this equation with the energy of the photon we get,

E=(13.6)(n12−n22n12n22) eV

Here n1 and n2 are the states in which transition takes place.

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