Find the derivative of the function and evaluate (x) at the given value of x. 3x + 1 fx) = %3D ;ズミ3 3x-1x f(x) = 3x-1' 6 1 %3D 3x 19 f(x) = - %3D 2 20 (3x + 1) 6. f(x) = - 2 (3x - 1) 32 f(x) = %3D 2 (6x - 1) 32 17 f(x) =-3(3x- 1)2- 18

sol only thank you.

Use the product rule to find the derivative of the function. y=(3x²+5) (2x-5) What is the correct way of writing the derivative of y? dy d OA. (3x²+5) (2x-5) dx (3x²+5)•(2x-5) = (3x² +5) • (2x-5) + (2x-5) • (3x²+5) dy O B. dx dy O c. dx dy d ( = (3x² +5) • (2x-5) + (2x-5)•(3x²+5) ○ D. dy dx dx = 則 dx d dx dx d d dx - (3x² +5) • 1x (2x-5)+ + (2x-5) • (3x²+5) dx dx