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Use the product rule to find the derivative of the function. y=(3x²+5) (2x-5) What is the correct way of writing the derivative of y? dy d OA. (3x²+5). (2x-5) dx dx dy (3x²+5)-(2x-5) OB. = (3x² + 5) • —— (2x − 5) + (2x-5) • —— (3x²+5) O C. OD. dy dx 55 dx dy ( = (3x² +5) • (2x-5) + —| (2x-5) • —— (3x²+5) dx dx · (x²+5)-(2x-5)+(2x-5)+(3x²+5)

Use the product rule to find the derivative of the function. y=(3x²+5) (2x-5) What is the correct way of writing the derivative of y? dy d OA. (3x²+5). (2x-5) dx dx dy (3x²+5)-(2x-5) OB. = (3x² + 5) • —— (2x − 5) + (2x-5) • —— (3x²+5) O C. OD. dy dx 55 dx dy ( = (3x² +5) • (2x-5) + —| (2x-5) • —— (3x²+5) dx dx · (x²+5)-(2x-5)+(2x-5)+(3x²+5)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use the product rule to find the derivative of the function. y=(3x²+5) (2x-5) What is the correct way of writing the derivative of y? dy d OA. (3x²+5) (2x-5) dx (3x²+5)•(2x-5) = (3x² +5) • (2x-5) + (2x-5) • (3x²+5) dy O B. dx dy O c. dx dy d ( = (3x² +5) • (2x-5) + (2x-5)•(3x²+5) ○ D. dy dx dx = 則 dx d dx dx d d dx - (3x² +5) • 1x (2x-5)+ + (2x-5) • (3x²+5) dx dx
Transcribed Image Text:Use the product rule to find the derivative of the function. y=(3x²+5) (2x-5) What is the correct way of writing the derivative of y? dy d OA. (3x²+5) (2x-5) dx (3x²+5)•(2x-5) = (3x² +5) • (2x-5) + (2x-5) • (3x²+5) dy O B. dx dy O c. dx dy d ( = (3x² +5) • (2x-5) + (2x-5)•(3x²+5) ○ D. dy dx dx = 則 dx d dx dx d d dx - (3x² +5) • 1x (2x-5)+ + (2x-5) • (3x²+5) dx dx
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