Find the critical value to for the confidence level c = 0.98 and sample size n = 23.t =Click the icon to view the t-distribution table.(Round to the nearest thousandth as needed.)t-Distribution Tabled.f.1234 or5678910111213141516171819202122232425Level ofconfidence, cOne tail, aTwo tails, a0.80 0.90 0.95 0.98 0.990.10 0.05 0.025 0.01 0.0050.20 0.10 0.05 0.02 0.013.078 6.314 12.706 31.821 63.6571.886 2.920 4.303 6.965 9.9251.638 2.353 3.1821.533 2.132 2.7764.541 5.8413.747 4.6041.476 2.015 2.571 3.365 4.0321.440 1.943 2.447 3.143 3.7071.415 1.895 2.365 2.998 3.4991.397 1.860 2.306 2.896 3.3551.383 1.833 2.262 2.821 3.2501.372 1.812 2,228 2.764 3.1691.3631.796 2.201 2.718 3.106 111.356 1.782 2.179 2.681 3.0551.350 1.771 2.160 2.650 3.0121.345 1.761 2.145 2.624 2.9771.341 1.753 2.131 2.602 2.9471.337 1.7462.9212.8982.120 2.5831.333 1.740 2.110 2.5671.330 1.734 2.101 2.552 2.8781.328 1.729 2.093 2.539 2.861 191.325 1.725 2.086 2.528 2.845 201.323 1.721 2.080 2.518 2.831 212.819 221.321 1.717 2.074 2.5082.807 231.319 1.714 2.0691.318 1.711 2.0642.5002.4921.708 2.060 2.4852.797 241.3162.787 25d.f.123456789DHZHS618100-X

We have given that c = 0.98 n = 23

Answered: Find the critical value to for the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 12 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 25 14 23 8 6 15 18 5 8 17 9 7 a. To compute the confidence interval use a ? z t Correct distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between blank and blank visits. c. If many groups of 12 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About # percent of these confidence intervals will contain the true population mean number of visits per patient and about # percent will not contain the true population mean number of visits per patient.
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