Find the critical value to for the confidence level c = 0.95 and sample size n = 11. Click the icon to view the t-distribution table. tc= (Round to the nearest thousandth as needed.)

Let x represent the hemoglobin count (HC) in grams per 100 milliliters of whole blood. The distribution for HC is approximately normal with μ = 14 for healthy adult women. Suppose that a female patient has taken 12 laboratory blood samples in the last year. The HC data sent to her doctor is listed below. We would like to know if the data indicates this patient has significantly high HC compared to the population.   14,19,16,14,19,19,14,21,17,17,14,17   Give the p-value and interpret the results. a) p = 0.0012; Based on 5% significance level, I will reject the null hypothesis and conclude this patient has a high HC level. b) p = 0.0012; Based on 5% significance level, I will fail to reject the null hypothesis and conclude this patient does not have a high HC level. c) p = 0.0023; Based on 5% significance level, I will reject the null hypothesis and conclude this patient has a high HC level. d) p = .1053; Based on 5% significance level, I will fail to reject the null hypothesis and…

Let x represent the hemoglobin count (HC) in grams per 100 milliliters of whole blood. The distribution for HC is approximately normal with μ = 14 for healthy adult women. Suppose that a female patient has taken 12 laboratory blood samples in the last year. The HC data sent to her doctor is listed below. We would like to know if the data indicates this patient has significantly high HC compared to the population. 22,17,20,17,17,14,16,21,15,21,15,22 Give the p-value and interpret the results. a) p = .1053; Based on 5% significance level, I will fail to reject the null hypothesis and conclude this patient does not have a high HC level. b) p = .0562; Based on 5% significance level, I will fail to reject the null hypothesis and conclude this patient does not have a high HC level. c) p = 0.0003; Based on 5% significance level, I will fail to reject the null hypothesis and conclude this patient does not have a high HC level. d) p = 0.0003; Based on 5% significance level, I will reject the…

I need the shade of the part of the curve corresponding to the calculation on both. On #1 and #2 since it was given thru this app when I submitted it. Thank you

For the residents in 2014, use R to calculate the interval with 99% certainty that the interval contains the actual population mean of the residents by census tracts. Type in the interval with keyboard. We also know that in each year, the number of residents by census tract in the State of Maryland follows a normal distribution, and the variance in the number of residents within the State of Maryland is the same for different years.  POP2014: 3072, 1989, 3794, 2689, 3211, 3722, 4385, 4009, 7598, 3862, 3097, 2726, 4881, 4157, 2570, 2512, 2518, 4863, 4147, 7139, 6067, 6819, 3705, 3239, 3824, 4977, 2576, 2940, 9791, 5231, 5634, 5337, 4205, 3888, 5562, 3335, 3770, 1808, 2045, 1532, 5420, 4993, 6109, 4377, 5424, 4976, 4507, 3738, 2827, 3485, 1559, 5199, 4702, 3971, 3803, 3356, 4670, 3816, 5477, 4760, 3126, 3630, 3755, 3795, 2578, 3382, 4005, 2442, 6096, 3799, 3843, 3836, 6046, 6431, 3561, 3142, 4829, 5058, 2471, 6119, 3523, 3094, 3146, 3356, 2618, 2366, 4266, 4016, 6080, 1554, 6878, 3645,…

The interquartile range is more susceptible to outliers in the data than is the range A. True B. False