Find the BER of a 64-QAM system with SNR=10 dB. NOTE: Use Q-function table as needed.
Q: Q5: a) Design a F.A with a decoder b) Design Hexadecimal to Binary Encoder.
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Q: (a), What is the basic. “limitation of SSB modulation scheme?. How is it climinated by VSB…
A: Limitation of SSB modulation scheme It requires complex receiver The generation of SSB modulation…
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A: You have posted multiple questions, so I will solve question 4 and 5 for you. 4)
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A: Given: VOH=4.5 V, V0L=0.5 V, VIH=4 V VIL=0.9 V RL=14 kΩRON=1 kΩ
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A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…
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A: The solution can be achieved as follows.
Q: ID = 50uA, W = 1u, L=0.5u, k’= 12uA/V2, Cgs = 48fF, Cgd = 77fF, Cgb
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Q: How many OC signals are combined into a 40 Gbps SONET network
A: D) 516096 From table 39813.12 Mbps i.e 40 Gbps the number of OC signals/channels combined are 516096
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A: The solution is given below
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Q: 1) The bandwidth of the input signal is 4 MHz. The PCM encoder uses 256 quantization levels. What is…
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Q: Determine the maximum bit rate and baud for a BPSK modulator with a carrier frequency of 50 MHz and…
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Find the BER of a 64-QAM system with SNR=10 dB. NOTE: Use Q-function table as needed.
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- The information in an analog signal voltage waveform is to be transmitted over a PCM system with an accuracy of : 0.1 % of the peak-to-peak analog signal. The analog voltage waveform has a bandwidth of 43 Hz and an amplitude range of - 10 to 10 Vots. Determine the minimum bit rate fin bps) required in the PCM system? O a 688 O 774 O c 387 O d 86 Oe 25810. A 150 mV level is to be converted into an 8-bit digital code. Calculate the resolution of the conversion, and analog levels represented by the MSB and LSB, and determine the analog level represented by 11111111.One of the disadvantages of PCM is a. It requires large bandwidth b. Very high noise c. Cannot be decoded easily d. All of the above
- Provide the ff 1.) expansion and conversion process 2.) canonical sop form of F' 3.) standard sop form of F'10-10. A 12-bit linear PCM code is digitally compressed into eight bits. The resolution = 0.03 V. Determine the following for an analog input voltage of 1.465 V: a. 12-bit linear PCM code b. eight-bit compressed code c. decoded 12-bit code d. decoded voltage e. compressed error f. total error g. percentage errorA) For the -K FFs shown below. Given the waveforms, Determine the Q output wave (PGT) CK B) Perform each of the following conversions: (0110.0000) BCD =(---s. (11100.1)2= (---- c d1001010) -6 (100010)- (-----)aray cod, (D3.E) 16- (-----) 2 BCD.
- What is meant as baud rate? I don't understand explain in bit details and what's the difference between baud rate and bit rate?C D .accepts this data and redistributes it to the n outputs. encoder De-multiplexer are faster in speed because the delay between the input and. * *.accepts this data and redistributes it to the n outputs. Decoder O output is due to the propagation delay of gate combinational circuit O Sequential network O Integrated circuit O Decoder O encoder O De-multiplexerPulse-code modulation (PCM) is the standard form of digital audio in computers, compact discs, digital telephony and other digital audio applications. Figure 3 shows the 3bit PCM system that transmit the 250 kHz analog signal with the voltage range from -6 mV to 6 mV. i) Identify the quantized value, voltage range and binary code for each level by building your own quantization table. ii) Calculate the minimum sampling rate and sampling time. ii) Identify the corresponding sampled voltage, the quantized voltage and binary code if the input signal is sampled at time t1 = 2us, t2 = 4us, t3 = 6us, t4 = 8µs. iv) Sketch the output in (iii) if it is fed to Manchester coding line encoder with bit rate of 20000 bit/sec and amplitude of +4 V. 5 4 3 2 10 Timel(usec) Figure 3 Amplitude (mV)
- A static VAR compensator consists of: A. TCRs in parallel with one or more TSCs B. Only TCR's C. Only TSC's D. TCRs in series with one or more TSCsWhat do you mean by fractional sampling rate conversion? Explain with an example of converting 48 kHz signal to 44.1 kHz signal using multi-stage fractional sampling rate converter3. What is the type of demodulation we used to demodulate SSB signal (part-A). Explain your answer.