Find the area in between z= 0.56 and z= -1.37 O 0.627 O -0.627 O 0.810 O -0.810

Q: The area between z = 0 and  z = −1.96 is

A: The are between z=-1.96 and z=0 is, P-1.96<z<0=Pz<0-Pz<-1.96 The probability of z less…

Q: Find the area if P(z>-1.30).

A:

Q: Find area under the curve between z= -0.3 and z= 1.97

A: X~N( μ , ?)μ=0    , ?=1 (for standard normal distribution)Z-score =( x - μ )/?

Q: The area to the right of z = 1 is approximately what? * O 0.460

A:

Q: Find the area A of the shaded region where b = 9. y = |x| + -b A =

A:

Q: Find the area to the left of z=.1.28 O 0.1020 O 0.1003 O 0.1030 O 0.1235

A: P(Z<-1.28) = 0.1003 (Using Excel = NORM.S.DIST(-1.28,TRUE))

Q: Find the area under the t-curve to the right of  t = 2.539 (degrees of freedom v =19 )

A: It is given that the t value is 2.539 and the test is right tail.

Q: A = Find the area A of the shaded region where b = 7. y y= |x| 0 -b b 0170

A:

Q: What is the area to the right of z=1.15?

A: Given z=1.15

Q: what is the area of the region to the right of z=-0.98?

A:

Q: Find the area From t=-2.539 to t=2.861 df=19

A: Given ,degrees of freedom(df)=19

Q: Find Z-score A such that an area between Z=1 and A is 0.15

A: Draw the normal curve and shade the approximate area of 0.15 between z=1 and z=A.

Q: Find Z-score A such that an area between Z=0.1 and A is 0.25

A:

Q: 69.74%

A: Consider mean of the probability distribution , μ=0. The standard deviation of the probability…

Q: Find the z-values whose area in both tails combined is approximately 0.18.   a. -0.36, +0.36   b.…

A: We have to find z score...

Q: Consider the matrix M over Z7, where M 1 1 6 2 6 41 425 = 5 2 350 624 1 2 1 4 3 (a) Compute rank(M)…

A: To find the rank, nullity, and null space of a matrix, you can follow these steps: Rank: The rank of…

Q: Estimate the area under the graph in the figure by using (a) the Trapezoidal Rule, (b) the Midpoint…

A:

Q: The area that lies between Z= 0.56 and Z= 0.89 is?

A: GivenThe area lies between z=0.56  and z=0.89

Q: Write the given (total) area as an integral. * The area above the x-axis and below y = 4 - x^2 *…

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Q: The area to the left of Z = 1

A: Area to the left of Z=1.63 is, PZ<1.63=0.9484 from the standard normal table

Q: Find the value of z such that 0.9108 of the area lies between −z and z.

A: Given, probability of the area lies between –z and z is 0.9108.

Q: The area between t = -1.321 and t = 1.321 can be found using 1 - 2(area to the right of t = 1.321).…

A:

Q: What is the z value such that? 1. The area between z and -z is 0.9010 2. The area between z= -1.21…

A: here use basic of normal distribution

Q: 10 1. 2 dx

A:

Q: Find the value of z such that 0.9426 of the area lies between −z and z.

A: It is given that the area 0.9426.

Q: ind the area to the right of z = 1.5

A: Given: z = 1.5 P (z > 1.5)

Q: Find the area if P(z>-1.30). O A. 0.0968 O B. 0.3708 O C. 0.4032 O D.0.9032

A:

Q: Find z when the area to the left of z is 0.3300 -0.44 -0.75 0.44 0.75

A: Given the area left to z is 0.33

Q: The area to the left of z = 0.43 is

A: The question is about std. normal dist. Given : z score ( z ) = 0.43   To find : The area to the…