Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Question

Find the area between 0 and 10

The image displays a definite integral:

\[
\int_{0}^{10} -1.2 \, dx
\]

### Explanation

This integral represents the area under the constant function \( f(x) = -1.2 \) from \( x = 0 \) to \( x = 10 \).

- **Function Description**: The function \( f(x) = -1.2 \) is a horizontal line located at \(-1.2\) on the y-axis.
- **Integral Calculation**:
  - The integral of a constant \( c \) over an interval \([a, b]\) is given by:
  \[
  \int_{a}^{b} c \, dx = c \times (b - a)
  \]
  - Applying this formula here:
  \[
  \int_{0}^{10} -1.2 \, dx = -1.2 \times (10 - 0) = -12
  \]
- **Graphical Interpretation**: The graph of \( f(x) = -1.2 \) spans from \( x = 0 \) to \( x = 10 \), forming a rectangle below the x-axis with a height of \(-1.2\). The value \(-12\) represents the net area of this region, indicating that the entire area is negative due to its position below the x-axis.
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Transcribed Image Text:The image displays a definite integral: \[ \int_{0}^{10} -1.2 \, dx \] ### Explanation This integral represents the area under the constant function \( f(x) = -1.2 \) from \( x = 0 \) to \( x = 10 \). - **Function Description**: The function \( f(x) = -1.2 \) is a horizontal line located at \(-1.2\) on the y-axis. - **Integral Calculation**: - The integral of a constant \( c \) over an interval \([a, b]\) is given by: \[ \int_{a}^{b} c \, dx = c \times (b - a) \] - Applying this formula here: \[ \int_{0}^{10} -1.2 \, dx = -1.2 \times (10 - 0) = -12 \] - **Graphical Interpretation**: The graph of \( f(x) = -1.2 \) spans from \( x = 0 \) to \( x = 10 \), forming a rectangle below the x-axis with a height of \(-1.2\). The value \(-12\) represents the net area of this region, indicating that the entire area is negative due to its position below the x-axis.
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