
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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"Find each of the following
a.p(z> 2.25)=
b.p(z>-1.20)=
c.p(z, <0.40)=
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- Let x be a normal random variable with its mean equal to 75 and standard deviation equal to 8. Find the following probabilities for this normal distribution. P(x > 89). Enter your answers using four decimal places.arrow_forwardLet x be a random variable representing dividend yield of bank stocks. We may assume that x has a normal distribution with = 3.3%. A random sample of 10 bank stocks gave the following yields (in percents). 5.7 4.8 6.0 4.9 4.0 3.4 6.5 71 5.3 6.1 The sample mean is x = 5.38%. Suppose that for the entire stock market, the mean dividend yield is u= 4.5%. Do these data indicate that the dividend yield of all bank stocks is higher than 4.5%?Use a = 0.01.arrow_forward. You make an investment. Assume that annual returns are normally distributed with a mean return of .05 per year and a standard deviation of .20. What is the probability of (a) a positive annual return? (b) What is the probability of an annual return greater than .12? (c) What is the probability of a return of –.06 or less? (d) Suppose there are 250 trading days in a year and the return on any day is independent of the return on any other day. What is the probability of a positive return on any given day?arrow_forward
- 1. Consider a Normal Distribution of Mean = 50 and Standard Deviation of 10. A. Find the Z-score of 75 B. Use probability calculator to approximate P(x > 75), round to the nearest ten- thousandth. C. Approximate the IQR for this Normal Distributionarrow_forwardAnswer Carrow_forward6.2 The Standard Normal Distribution Table: Z-score and Probability A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 164.7 cm and a standard deviation of 2.5 cm. Find the probability that the length of a randomly selected steel rod is greater than 167.7 cm. Probability -arrow_forward
- Find each of the probabilities, where z is a z-score from the standard normal distribution with mean of p =0 and standard deviation o = 1. Round to four decimal places, if necessary. P(z 0.39) = P(0 < z< 2.56) = P(-2.72arrow_forwardAssume that the distributions for the following scenarios are normal. Use the normal standard table to find the following probabilities. Round z-scores to the nearest hundredth. 1. The average score on a math test is 75 with a standard deviation of 8. What is the probability that a randomly selected test has a score of 90 or higher? P(z 2. The life of a gas grill is 3.5 years with a standard deviation 0.35 years. What is the probability that the grill will last less than 3 years? P(z 3. Ambulance response times average 7.5 minutes with a standard deviation of 2.5. What is the probability that an ambulance will respond within 6 to 8 minutes. P(arrow_forwardFind each of the following probabilities for a normal distribution. Write a statement for each answer (e.g., “The probability of find a score between..... is .......”). p(-1.80 < z < +0. 20) p (-0.90 < z < -0.60)arrow_forward
- For a normal distribution with a mean of µ=100 and a standard deviation of σ= 15, find each of the following probabilities: a. p(X>108) p= b. p(X<80) p= c. p(X<125) p= d. p(90<X<110) p=arrow_forwardSuppose that the random variable z has a standard normal distribution. Sketch each of the following z points, and use the normal table to find each z point. a) z(-0.01)b) z(-0.05)c) z(-0.10)arrow_forward10. Find each of the following probabilities for a normal distribution. a. p(-1.80 < z < 0.20) b. p(-0.40 < z < 1.40) c. p(0.25 < z < 1.25) d. p(-0.90 < z < -0.60)arrow_forward
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