Fill in the blanks with the correct terms. Sex-linked traits have genes located on the chromosomes. They are most often found on the chromosome because it is larger than the chromosome. get the recessive sex linked traits more often than because they only have X chromosome.
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- Mutations in DNA that result in altered proteins can causehereditary diseases. Pedigree studies and genetic testing mayclarify the risk of disease. At the chromosome level, nondisjunctionduring meiosis can result in gametes with too few or too manychromosomes, most of which produce inviable offspring.Imprinting refers to inactivation of alleles depending on whichparent the alleles come from; offspring in whom imprinting occursappear haploid for the affected gene even though they are diploid. During spermatogenesis, is there any difference in outcome between first- and second-division nondisjunction?The maternal-effect mutation bicoid (bcd) is recessive. Inthe absence of the bicoid protein product, embryogenesis isnot completed. Consider a cross between a female heterozygousfor the bicoid mutation (bcd+/ bcd-) and a homozygousmale(bcd-/ bcd-). Predict the outcome (normal vs. failed embryogenesis) inthe F1 and F2 generations of the cross described.In humans, an X-linked disorder called coloboma iridia (a fissure in the iris_ is a recessive trait. A normal couple has an afflicted daughter. What would be the most plausible scenario for this situation? the female is not the biological mother, but the male is the biological father the father carries one recessive allele, and the mother carries one recessive allele the mother carries two recessive alleles the male is not the biological father, but the female is the biological mother both parents are heterozygous for the trait
- Color-blindness is an X-linked recessive disorder. Under what circumstances will this condition manifest in a child? Top of Form If the child is a male and its mother has the recessive allele If the child is a female and its father has the recessive allele If the child is a female and its mother has the recessive allele If the child is a male and its father has the recessive alleleMen have XY (or YX) chromosomes and women have XX chromosomes. X-linked recessive genetic diseases (such as juvenile retinoschisis) occur when there is a defective X chromosome that occurs without a paired X chromosome that is not defective. Represent a defective X chromosome with lowercase x, so a child with the xY or Yx pair of chromosomes will have the disease and a child with XX or XY or YX or xX or Xx will not have the disease. Each parent contributes one of the chromosomes to the child. Complete parts a through d below. a. If a father has the defective x chromosome and the mother has good XX chromosomes, what is the probability that a son will inherit the disease? nothing (Type an integer or a decimal. Do not round.) b. If a father has the defective x chromosome and the mother has good XX chromosomes, what is the probability that a daughter will inherit the disease? nothing (Type an integer or a decimal. Do not round.) c. If a mother has one defective x…Haemophilia is an X-linked recessive disorder. If a woman is a carrier for haemophilia and has a child with a man who does not have haemophila, what is the probability of them having a child who has haemophilia? 75% of their children will have haemophilia. 25% of their children will have haemophilia. 100 % of their children will have haemophilia. 50% of their children will have haemophilia. 82% C F5 F4 F6 F7 F8 F9 F10 F11 * 4. 7 V 8 A 9 R Y JG YHIJ-K L/ * CO ( CO
- Red-green color blindness is inherited as a sex-linked recessive trait. The gene is found on the X chromosome. How can a man with normal color vision father a daughter who is red-green color-blind? Group of answer choices The man is heterozygous for red-green color blindness. The woman with whom he mates is red-green color-blind. He can't (unless there is a mutation). The man's mother carries an allele for red-green color blindness, and the expression of the trait skipped a generation.The most common form of colorblindness is a recessive, sex-linked hereditary con dition caused by a defect on the X chromosome. Females are XX, while males are XY. Individuals inherit one chromosome from each parent, with equal probability; for example, an individual has a 50% chance of inheriting their father's X chromosome, and a 50% chance of inheriting their father's Y chromosome. If a male has an X chromosome with the defect, he is colorblind. However, a female with only one defective X chromo some will not be colorblind. Thus, colorblindness is more common in males than females; 7% of males are colorblind but only 0.5% of females are colorblind. (a) Assume that the X chromosome with the wild-type allele is X+ and the one with the disease allele is X. What is the expected frequency of each possible female genotype: X+X+, X+X¯, and X-X-? What is the expected frequency of each possible male genotype: X+ Y and X-Y? (b) Suppose that two parents are not colorblind. What is the…Consider a rare disease that is X-linked recessive. A normal man is married to a normal woman with no family history of the disease. They have an affected child. What can you deduce from this? Choose the most correct option. -The child is a carrier of the disease allele, and she is a daughter. -The child is a carrier of the disease allele, and he is a son. -Their child is a daughter. -The child is likely adopted. -Their child is a son.
- Draw a Punnett square for the dihybrid cross. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage.In humans color vision is X-linked, the gene for color vision is located on the X chromosome but is absent on the Y chromosome. Normal color vision (XN) is dominant over colorblindness (Xn). Suppose a colorblind man fathers the children of a woman with genotype XNXN. What is the genotype of the father? What proportion of daughters will be colorblind? What proportion of the sons will be colorblind?The XG locus on the human X chromosome has twoalleles, XG+ and XG. The XG+ allele causes the presence of the Xg surface antigen on red blood cells,while the recessive XG allele does not allow antigento appear. The XG locus is 10 m.u. from the STSlocus. The STS+ allele produces normal activity ofthe enzyme steroid sulfatase, while the recessive STSallele results in the lack of steroid sulfatase activityand the disease ichthyosis (scaly skin). A man withichthyosis and no Xg antigen has a normal daughterwith Xg antigen. This daughter is expecting a child.a. If the child is a son, what is the probability he willlack Xg antigen and have ichthyosis?b. What is the probability that a son would have boththe antigen and ichthyosis?c. If the child is a son with ichthyosis, what is theprobability he will have Xg antigen?